Pythagoras theorem ! (a²+b²=c²)
Q1) AC = √4.8²+3.6²
= √36
= 6cm
Q2) AB= √17.55² - 6.75²
= √262.44
= 16.2cm
Q3) BC= √14² - 6²
= √160
= 12.64911
= 12.6 cm (to 3sf)
The answer is 192 y^8.
(4y^2)^3 = 64y^6
64y^6 • 3y^2= 192y^8
When “multiplying” a number with an exponent, you add the 2 exponents.
Answer:
-3/2
Step-by-step explanation:
If the first equation is 9x +3/4y = 6, then the solution would look like this:
An appropriate multiplier is -3/2.
Well, mode means most frequent number within the set so since there is two 18's that is your mode.
