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SOVA2 [1]
4 years ago
14

What is the value of the expression shown below? 3 over 6 to the power of 2 + 7 × 4 − 5

Mathematics
2 answers:
podryga [215]4 years ago
3 0
I believe the answer would be 24 for this equation
kvv77 [185]4 years ago
3 0
3/6^2+7x4-5
You have to use PEMDAS
So first you would do the parentheses but you don't have any so you would do exponents so
3/6^2 which is 3/6x3/6= 9/36 and you would simplify that to 1/4.

Then you do multiplication and division. (It doesn't matter which order you do this in) so you would do 7x4=28

Then you do addition and subtraction (doesn't matter which order you do this one either. You have to do which ever comes first in the problem, just like in multiplication and division) so

1/4+28-5
28 1/4-5= 23 1/4

You answer is 23 1/4 I hope this helped :)
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A fair coin is flipped 10 times and lands on heads 8 times. Provide a reason to justify the difference between the experimental
professor190 [17]

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THere will be 8 heads and 2 tails

Step-by-step explanation:

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5 0
3 years ago
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7 0
3 years ago
Write a rule for the nth term of the geometric sequence if r=1/4 and a<br> =6
Shalnov [3]

Answer:

a(n) = a(1)*(1/4)^(n-1)

Step-by-step explanation:

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Then the general formula for this sequence is

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5 0
3 years ago
WILL GIVE A BRAINLIEST
skelet666 [1.2K]
Find slope
slope betwen 2 points (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)

so
first make denoms same
denom is 10
(4/5,1/5) turns to (8/10,2/10)
(1/2,3/2) turns to (5/10,15/10)
slope=(15/10-2/10)/(5/10-8/10)=(13/10)/(-3/10)=13/-3=-13/3

use point slope
use (4/5,1/5)
y-y1=m(x-x1)
a point is (x1,y1) and slope is m
y-1/5=-13/3(x-4/5)
expand
wait, we don't need to do that, the only one with slope -13/3 is D
answer is D
4 0
3 years ago
Identify the FIVE numbers which have a square root that lies between the whole numbers 4 and 12 (Does not im
AysviL [449]

Answer:

25,16,121,49

5 is the sqaure root of 25 4 is the sqaure root of 16 11 is the square root of 121 and 7 is the square root of 49

50,145,20, and 8 do not have square roots.

6 0
4 years ago
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