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3 years ago

Mckenzie bought 1.2 pounds of coffee for 11.82 what was cost of per pound

Mathematics

1 answer:

borishaifa [10]3 years ago

3 0

first you divide 1.2 by its self because you need to get 1 pound. 1.2 / 1.2 = 1

now that you have one pound, you divide 11.82 by 1.2 = 9.85

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Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl

Karo-lina-s [1.5K]

Full Question

Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordless, and the other six are corded phones. Suppose that these components are randomly allocated the numbers 1, 2, . . . , 18 to establish the order in which they will be serviced.

What is the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced?

What is the probability that two phones of each type are among the first six serviced?

Answer:

a. 0.149

b. 0.182

Step-by-step explanation:

Given

Number of telephone= 18

Number of cellular= 6

Number of cordless = 6

Number of corded = 6

There are 18C6 ways of choosing 6 phones

18C6 = 18564

From the Question, there are 3 types of telephone (cordless, Corded and cellular)

There are 3C2 ways of choosing 2 out of 3 types of television

3C2 = 3

There are 12C6 ways of choosing last 6 phones from just 2 types (2 types = 6 + 6 = 12)

12C6 = 924

There are 2 * 6C6 * 6C0 ways of choosing none from any of these two types of phones

2 * 6C6 * 6C0 = 2 * 1 * 1 = 2.

So, the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced is

3 * (924 - 2) / 18564

= 3 * 922/18564

= 2766/18564

= 0.149

There are 6C2 * 6C2 * 6C2 ways of choosing 2 cellular, 2 cordless, 2 corded phones

= (6C2)³

= 3375

So, the probability that two phones of each type are among the first six serviced is

= 3375/18564

= 0.182

5 0

3 years ago

A publisher requires 2⁄3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest

rjkz [21]

Let x be the number of pages of advertisements.

Write a proportion from the table:

$\dfrac{2}{3}$ of a page of advertisment - 5 pages in a magazine

x pages of advertisment - 98 pages in a magazine,

then

$\dfrac{\dfrac{2}{3}}{x}=\dfrac{5}{98}.$

Find x:

$x=\dfrac{\dfrac{2}{3}\cdot 98}{5}=\dfrac{196}{15}=13\dfrac{1}{13}.$

Answer: 13 whole pages and $\dfrac{1}{13}$ of 14th page are advertisments, so 14 pages contain advertisments.

3 0

3 years ago

What is the missing expression? x 8 + 3x 5 = x5(_____)

Andrej [43]

We have to factor the polynomial.

x^8+3x^5

Find the GCF between 1,3,x,5,8

The GCF is x^5

Divide the polynomial by x^5

x^5(x^3+3)

4 0

3 years ago

Find an equation for the nth term of the arithmetic sequence. 9, 11, 13, 15...

saul85 [17]

Answer:

2n+7

Step-by-step explanation:

find the difference

and see the difference from the 2 Times table to the original sequence

and write it as an equation for this sequence

3 0

3 years ago

Read 2 more answers

Dylan delivers parcels.

vovikov84 [41]

Answer:

Dylan delivered 140 parcels on Wednesday.

Step-by-step explanation:

On Wednesday:

On Wednesday, he delivered x parcels.

Thursday:

10% more than Wednesday, so 100 + 10 = 110% of x = 1.1x

Friday:

50% pless than on Thursday, so 100 - 50 = 50% of 1.1x = 0.5*1.1*x.

THis is equals to 77. So

$0.5*1.1x = 77$

$x = \frac{77}{0.5*1.1}$

$x = 140$

Dylan delivered 140 parcels on Wednesday.

5 0

3 years ago