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3 years ago

What values for θ (0 ≤ θ ≤ 2pie ) satisfy the equation?

1 answer:

7 0

Factor out the cosθ:
cosθ (2sinθ + sqrt3) = 0
Therefore, the only ways this can happen are if either cosθ = 0 or if (2sinθ + sqrt3) = 0
The first case, cosθ = 0 only at θ = pi/2, 3pi/2.
The second case, (2sinθ + sqrt3) = 0 simplifies to:
sinθ = (-sqrt3)/2
θ = 4pi/3, 5pi/3
Therefore the answer is A.

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If someone is good at Precalculus or Physics, please help me solve this.

Kobotan [32]

Magnitude of vector V =√(3²+7²) = √58

Hence: U= -3/√58 - 7/√58

OR multiply numerator and denominator by √58

U = - (3√58)/58 i - (7√58)/58 j

8 0

2 years ago

The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2

svetlana [45]

Answer:

The equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1$ .

Step-by-step explanation:

Given

The equation of ellipsoid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1$

The equation of tangent plane at the point $\left(x_0,y_0,z_0\right)$

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1$ ( Given)

The equation of hyperboloid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1$

F(x,y,z)= $\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}$

$F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}$

$(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)$

The equation of tangent plane at point $\left(x_0,y_0,z_0\right)$

$\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0$

The equation of tangent plane to the hyperboloid

$\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0$

The equation of tangent plane

$2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2$

Hence, the required equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0$

7 0

3 years ago

What is the answers?

34kurt

Cos theta would be (adjacent side) / (hypotenuse), or 8/29.

Thus, the angle theta would be the inverse cosine of 8/29, which is

1.291 radians or 73.987 degrees.

Given this result, just take the sine of this angle.

6 0

3 years ago

HELP ASAP solving the identity, tan (A) =

Luba_88 [7]

Answer:

Its 7/3 or the second one

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which is a list of all the zeros of x^5 + 7x^4 = 18x³?

Andrei [34K]

Answer:

Step-by-step explanation:

Because there is three numbers

3 0

2 years ago