What values for θ (0 ≤ θ ≤ 2pie ) satisfy the equation?

1 answer:

7 0

Factor out the cosθ:
cosθ (2sinθ + sqrt3) = 0
Therefore, the only ways this can happen are if either cosθ = 0 or if (2sinθ + sqrt3) = 0
The first case, cosθ = 0 only at θ = pi/2, 3pi/2.
The second case, (2sinθ + sqrt3) = 0 simplifies to:
sinθ = (-sqrt3)/2
θ = 4pi/3, 5pi/3
Therefore the answer is A.

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