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Gemiola [76]
3 years ago
12

lass="latex-formula">
Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0

Your answer would be 9.11

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Cylinder has a height of 15 centimeters and a radius of 10 centimeters. What is its volume? Use ​ ≈ 3.14 and round your answer t
tatuchka [14]

Answer: 4712.39 centimeters

Step-by-step explanation: Using the volume of a cylinder calculator, I got the answer of 4712.3889803847 centimeters, but rounded it to the nearest hundreth. Hope this helps!

3 0
3 years ago
Someone help please!
saveliy_v [14]

Answer:

BC ≈ 14.7 m

Step-by-step explanation:

Using the Sine rule in Δ ABC

\frac{AB}{sinC} = \frac{BC}{sinA}

To find ∠ A subtract the 2 given angles from 180°

∠ A = 180° - (90 + 28)° = 180° - 118° = 62°

Then

\frac{7.8}{sin28} = \frac{BC}{sin62} ( cross- multiply )

BC × sin28° = 7.8 × sin62° ( divide both sides by sin28° )

BC = \frac{7.8sin62}{sin28} ≈ 14.7 m ( to 3 significant figures )

5 0
3 years ago
The value of the x-intercept for the graph of 4x-5y=40 is<br> 1) 10<br> 2) 4/5<br> 3) -4/5<br> 4) -8
borishaifa [10]

Answer:

I took it and got this question anf got it correct! Hope i helped!

Step-by-step explanation:

- 8

7 0
3 years ago
Read 2 more answers
Which of the following is the solution set of x² + 8x + 12 = 0?
raketka [301]

Answer:

\fbox{\begin{minipage}{9em}x = -2 and x = -6\end{minipage}}

Step-by-step explanation:

Given:

x^{2} + 8x + 12 = 0

Solve for:

x

Solution:

Step 1: Select the formula to solve for x

There are some ways to solve quadratic equations.

One of the simple way (if possible) is performing the factorization.

Another way is using the quadratic formula.

Here, we are going to use factorization.

Step 2: Perform factorization

      x^{2} + 8x + 12 = 0

<=>x^{2}  +  2x + 6x  + 12 = 0

<=>(x^{2} + 2x) + (6x + 12) = 0

<=>x(x + 2) + 6(x + 2) = 0

<=>(x + 2)(x + 6) = 0

<=> x = -2 or x = -6

Hope this helps!

:)

4 0
3 years ago
In the inequality 6a+4b&gt;10, what could be the possible value of a if b=2?
Arlecino [84]

We are given the following inequality:

6a+4b>10

If we replace b = 2, we get:

\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}

Now we solve for "a" first by subtracting 8 on both sides:

\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}

Now we divide both sides by 6

\frac{6a}{6}>\frac{2}{6}

Simplifying:

a>\frac{1}{3}

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3

3 0
1 year ago
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