<img src="https://tex.z-dn.net/?f=14.25%20-%205.14" id="TexFormula1" title="14.25 - 5.14" alt="14.25

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Gemiola [76]

3 years ago

lass="latex-formula">

Mathematics

1 answer:

Whitepunk [10]3 years ago

3 0

Your answer would be 9.11

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model aeroplane is made to a scale of 1 by two of the size of the real plane the area of the wings of the real plane are 40 m sq

4vir4ik [10]

The area of the wings of the model is 100000 square centimeters

<h3>How to determine the model area of the wings?</h3>

The given parameters are:

Scale factor, k = 1/2

Actual area of wings, A = 40 square meters

The model area is calculated as

Model area = Actual area * k^2

This gives

Model area = 40 * (1/2)^2

Evaluate

Model area = 10 square meters

Convert square meters to square centimeters

Model area = 10 * 10000 square centimeters

Evaluate

Model area = 100000 square centimeters

Hence, the area of the wings of the model is 100000 square centimeters

Read more about scale ratios at:

brainly.com/question/16192120

#SPJ1

6 0

2 years ago

The perimeter of an equilateral triangle is 3 (+ 5). The perimeter of a rectangle is 2 (2x - 3) + 2(2). If the perimeters of the

TiliK225 [7]

Answer:

3.25

Step-by-step explanation:

Perimeter of triangle = 3(5) = 15 cm

Perimeter of rectangle = 2(2x - 3 + 4)

Perimeter = 2(2x + 1)

Perimeter = 4x + 2

4x + 2 = 15

4x = 15 - 2

4x = 13

x = 13/4

x = 3.25

5 0

3 years ago

PLS I GIVE BRAINLIEST

matrenka [14]

The size of the angle QUP in the system formed by the equilateral triangle QUR, the equilateral triangle PUT and the square RUTS is equal to 150°.

<h3>How to determine a missing angle within a geometrical system</h3>

By Euclidean geometry we know that squares are quadrilaterals with four sides of equal length and four right angles and triangles are equilateral when its three sides have equal length and three angles with a measure of 60°. In addition, a complete revolution has a measure of 360°.

Finally, we must solve the following equation for the angle QUP:

m∠QUR + m∠QUP + m∠PUT + m∠RUT = 360

60 + m∠QUP + 60 + 90 = 360

m∠QUP + 210 = 360

m∠QUP = 150

The size of the angle QUP in the system formed by the equilateral triangle QUR, the equilateral triangle PUT and the square RUTS is equal to 150°. $\blacksquare$