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makkiz [27]
3 years ago
7

Tony writes an equation to represent the distance he walks in meters, d, in relation to the number of minutes he walks, m. d = 1

08m Mark has created a table to record the number of minutes it took him to walk different distances in meters. Time (minutes) Distance (meters) 10 1,100 20 2,200 40 4,400 Assuming that Tony and Mark both walk at a constant rate, the unit rate for Tony is meters per minute and the unit rate for Mark is meters per minute. On a graph, the line representing Tony’s distance covered with respect to time would be Mark’s line. So, Tony’s walking speed is Mark’s.
Mathematics
2 answers:
anastassius [24]3 years ago
7 0

Answer:

Tony : d = 108m.....so Tony walks 108 meters per minute

Mark :

(10,1100),(20,2200)

slope = (2200 - 1100) / (20 - 10) = 1100/10 = 110 meters per minute

So Tony's walk speed is 2 meters per minute slower then Tony's walk speed

Step-by-step explanation:  i just did it and got it right

liraira [26]3 years ago
6 0
Tony : d = 108m.....so Tony walks 108 meters per minute

Mark :
(10,1100),(20,2200)
slope = (2200 - 1100) / (20 - 10) = 1100/10 = 110 meters per minute

So Tony's walk speed is 2 meters per minute slower then Tony's walk speed
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and "x" is how many seconds you've been in the elevator.

now, she got in the elevator for 6 seconds, so, the elevator went down by 20 * 6, or 120 feet down, reason why the slope is negative, when she stopped, she was 350 feet away from the ground floor still though.

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b)

\bf \begin{array}{lcccllll}
&\stackrel{\textit{elapsed seconds}}{x_1}&\stackrel{\textit{ft from ground-floor}}{y_1}\\
%   (a,b)
&({{ 6}}\quad ,&{{ 350}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies -20
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-350=-20(x-6)
\\\\\\
y-350=-20x+120\implies  y=-20x+\stackrel{y-intercept}{470}
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