Answer:
sqrt(x-3)+3
Step-by-step explanation:
Consider the graph of a function f(x), if we want to move the graph right by a units we have f(x-a), to then move it up by b units we have f(x-a)+b. In this case you replace the x with x-a to get sqrt(x-a)+b
Notice how the graph goes through (3,3) and (4,4) like the original graph goes through (0,0) and (1,1). This means we want to translate it 3 up and 3 right giving us the answer.
Answer:
You forgot to give us an image, please go do that
Step-by-step explanation:
Note:xy means x times y and x(y) means the same thing
so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0
squareroot(y-1)+3=y
isolate the squareroot
subtrac 3 from boht sides
squareroot(y-1)=y-3
square both sides (since they are equal, you should be able to square both sides and still make it true)
(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5
0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0
therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work
let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true
y=5
