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Leya [2.2K]
3 years ago
6

There are 3 cats in the room and no other creatures. Each cat has 2 ears, 4 paws, and 1 tail.

Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

ears to paws to tails,

which is 6 to 12 to 3.

4 paws to every tail.

2 paws to every ear.

Step-by-step explanation:

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F is between E and G. EF=3X, EG= 11x-2, FG= 5x+16. Find the value of the variable
Salsk061 [2.6K]

9514 1404 393

Answer:

  x = 6

Step-by-step explanation:

The sum of segments is used:

  EF +FG = EG

  3x +(5x +16) = 11x -2 . . . . substitute given expressions

  8x +18 = 11x . . . . . . . . add 2

  18 = 3x . . . . . . . . subtract 8x

  6 = x . . . . . . divide by 3

The value of the variable is 6.

__

<em>Check</em>

The segment lengths are ...

  EF = 3x = 3·6 = 18

  FG = 5x+16 = 5·6 +16 = 46

  EG = 11x -2 = 11·6 -2 = 64 = 18+46 . . . answer is correct

3 0
3 years ago
3b 2a=5a−6 solve the equation for a in terms of <br> b.
oee [108]
Is it 3b-2a=5a-6
or
3b+2a=5a-6

you are missing the sign of 2a
4 0
3 years ago
Condense the following logarithm: <br><img src="https://tex.z-dn.net/?f=5%20log_%7B4%7D%28a%29%20%20-%206%20log_%7B4%7D%28b%29%2
aleksley [76]

log 4 ( a^5 ) - log 4 ( b^6 ) =

log 4 ( a^5 / b^6 )

4 0
3 years ago
he number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.02
Yakvenalex [24]

Answer:

a) 98.01%

b) 13.53\%

c) 27.06%

Step-by-step explanation:

Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2  

If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,

P(k)= \frac{0.2^ke^{-0.2}}{k!}

a)

In this case, we are looking for P(0)

P(0)= \frac{0.2^0e^{-0.2}}{0!}=e^{-0.2}=0.9801=98.01\%

So, the probability that a car has no flaws is 98.01%

b)

Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.

Now P(k) is the probability that 10 cars have k flaws and  

P(k)= \frac{2^ke^{-2}}{k!}

and  

P(0)= \frac{2^0e^{-2}}{0!}=0.1353=13.53\%

And the probability that 10 cars have no flaws is 13.53%

c)

Here, we are looking for P(1) with P defined as in b)

P(1)= \frac{2^1e^{-2}}{1!}=2e^{-2}=0.2706=27.06\%

Hence, the probability that at most one car has no flaws is 27.06%

6 0
3 years ago
Read 2 more answers
Please answer this correctly without making mistakes
Len [333]

Answer:

The 2-yard pièce of cotton cloth for $13.26

Step-by-step explanation:

2 yards is 6 feet then it would be $2.21 per foot.

The 17 foot piece would cost $3.29 per foot.

6 0
3 years ago
Read 2 more answers
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