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2 years ago

6

A farmer had large herd of goats. Besides the 4 goats that slept in his bed, he had 7 barns full of goats. How many goats were i

n each barn if his herd totaled 95 goats? Write an equation that represents this situation. (2 part problem)

1 answer:

fiasKO [112]2 years ago

6 0

95-4=91 then 91 divided 7=13 (95-4) divided 7=13

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A ship travels 62.5 km in 1st hour of sailing. Starting from 2nd hour, the distance travelled per hour is x% of that in the prec

Bas_tet [7]

Speed of the ship in the second hour = (62.5 * x ) / 100 kph.

In third hour it is [(62 * x) / 100 ] * x/100]

is 4th hour its is the above * x/100 again so we can now form the equation

62.5x x x
------- * ---- * ---- = 32
100 100 100

62,5 x^3 = 32,000,000
x^3 = 512,000
x = 80 <----- Answer to (a)

(b) Ship travels 62.5 in first hour then this falls by a common ratio of 0.8 each hour so we have a geometric sequence

Dist travelled in 6 hours = a1 1 - r^n
-------- = 62.5* (1 - 0.8^6) / 1 -0.8 = 230.56

1 - r

Answer is 230.56 km

5 0

3 years ago

if danny jogged 8x-21 miles and julie jogged 24x-63 mike’s, how many times longer was julie’s travel distance than danny’s?

Bas_tet [7]

Julie traveled 3 times more miles than Danny.
This is because 24x is 3 times more than 8x and -63 is 3 times more than -21.

6 0

2 years ago

Read 2 more answers

Sketch, mark and label the following (GEOMETRY)

nordsb [41]

Answer: See the pictures

Step-by-step explanation:

Hope I helped!

Sorry it took so long btw

3 0

3 years ago

Please I need help with this!!!!!!!

inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

$x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}$

$x=\sqrt[3]{5^4}$ [Since, $a^{\frac{1}{3}}=\sqrt[3]{a}$ ]

$x=\sqrt[3]{5\times 5\times 5\times 5}$

Step 5:

$x=\sqrt[3]{(5)^3\times 5}$

$x=\sqrt[3]{5^3}\times \sqrt[3]{5}$

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

$(3x-1)^{\frac{1}{5}}=2$

Step 1:

$(3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}$

Step 2:

$(3x-1)=2^5$

Step 3:

$3x=32+1$

Step 4:

$x=11$

4). By substituting $x=11$ in the original equation.

$(3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}$

$=(2^5)^\frac{1}{5}$

$=2$

There is no extraneous solution.

3 0

2 years ago

Which best describes the relationship between the line that passes through the points (1, –6) and (3, –2) and the line that pass

Setler [38]

Both lines are parallel, since they have the same slope of 2.

8 0

3 years ago