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mars1129 [50]
3 years ago
9

Answer that for me please i am very confused

Mathematics
2 answers:
madreJ [45]3 years ago
4 0
They are asking how to rewrite the equation with it as x= what ever comes after
example 4*x=20  so x= 20/4
Alex787 [66]3 years ago
4 0
The answer is A f(X)=X+4  
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ANSWER QUICKLYYYYYY!!!
myrzilka [38]

Answer:

AC = 16.5

AE = 9

Step-by-step explanation:

Connect AC and BE

Note m∠ACD = m∠ACB, (both face arc BD)

ΔACD ~ ΔABE

AD : AB = AC : AE

6 : 4 = AC : (6 + 5)

3 : 2 = AC : 11

2AC = 3*11 = 33

AC = 16.5

AE = 9

7 0
2 years ago
Write an equation of the line passing through the given point and satisfying the given condition. Give the equation (a) in slope
Doss [256]

Answer:

hii friends and you also follow me and give me brainliest ok by

5 0
3 years ago
Read 2 more answers
a.Two 7-sided fair dice are tossed simultaneously. What is the probability of getting two sevens? b.Two 7-sided fair dice are to
Brrunno [24]

A).
The first cube can land in any one of 7 ways. For each of those . . .
The second cube can land in any one of 7 ways.

Total number of possible results = (7 x 7) = 49 .

Number of successful results (both land on 7s) = 1

Probability = 1/49 =  2.04% .

B).
This is a trick question.
Two dice can only show 2 numbers at a time.
The probability of any combination of 3 numbers is zero.

3 0
3 years ago
Which polynomial identity will prove that 64+27=91
Kipish [7]
8^3+3^3

27=3*3*3
64=8*8*8
8 0
4 years ago
Read 2 more answers
Estadio Azteca, a stadium in Mexico City, has a capacity of 1.04 X 10 to the 5th power people. One day,
Irina-Kira [14]

Answer:

The average number of people who entered the stadium per minute was 4,160

Step-by-step explanation:

we know that

To find out the average number of people who entered the stadium per minute, divide the total number of people by the time required to fill the stadium

Let

x ----> the total number of people

y ----> the time required to fill the stadium

we have

x=1.04*10^{5}\ people

y=25\ min

so

\frac{1.04*10^{5}}{25}= 4,160\frac{people}{minute}

therefore

The average number of people who entered the stadium per minute was 4,160

4 0
4 years ago
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