Answer:



---
---
-

Step-by-step explanation:
Given
--- perimeter


Required
Possible dimension of different parallelogram
The perimeter is calculated as:

So,we have:

Divide by 2

Since l and w must be positive integers, the possible dimensions are:



---
---
-

The function represents the profit, and the company obviously wants to maximize it.
You can see that the profit increases until the parabola reaches its maximum.
The coordinate of the maximum look like (1.5, 90)
This means that, if the company invests 1.5 thousand dollars, the profit will be 90 thousand dollars, and this is the maximum profit the company can reach.
False. they could be skew
..................
..
.....
We have been given the expression

We can rewrite the expression as 
In order to simplify the given expression, we can check if we have any common terms in the numerator and denominator.
We can write the term 72 which is in the numerator as 
Thus, the expression becomes

We can see that 4 is common in both numerator and denominator. Hence, we can cancel 4. Thus, we are left with

Therefore, we can rewrite the given expression as 54.
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>