That is (t^9)^-8
= t^(9*-8)
= t^-72 or 1 / t^72
The answer for this problem is associative property
1)
a) Draw the axis:x-axis is horizontal, y-axis is vertical
b) draw a point on any part of the plane (use color to highlight it)
c) draw a second point on a different part of the plane (again use color)
d) draw the straight line that passes through the two points (use a ruler).
That is it.
2)
a) Draw the axis: x-axis is horizontal and y-axis is vertical
b) Draw a stright line (use a ruler)
c) Draw a second straight line (use a ruler) which is not parallel to the first line. Extend the second line intil it intersects (and passes) the first line. The lines can only intersect in one point (if the lines are parallel they will not intersect each other).
Answer:
RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)
(x-11/2)/(x-4)
Step-by-step explanation:
Ok we need to simplify the expression so:
x^2+3x-10= Bhaskara formula=
-3(±√9-4·1·(-10))/2·1=
X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2
X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2
x^2-6x+8= Bhaskara formula=
6(±√36-4·1·8)/2·1=
X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2
X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4
so, The simplify expression is
(x-2)·(x-11/2)/(x-2)(x-4)=
Answer: the expression (120/100)*80 results in 80% of 120
Step-by-step explanation:
