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3 years ago

7

What are the factor pairs of 29

1 answer:

Katyanochek1 [597]3 years ago

7 0

Answer:

(-29,-1) and (29,1)

Step-by-step explanation:

29 is a prime number so these are the only factor pairs.

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80% of 15 plus fraction

lana [24]

Answer:

Idk what u mean by fraction but 80% of 15 is 12

Step-by-step explanation:

7 0

3 years ago

Assume that the random variable X is normally distributed, with mean mu equals 100 and standard deviation sigma equals 20. Comp

TEA [102]

Answer: 0.2119

Step-by-step explanation:

We assume that the random variable X is normally distributed.

Given : Population mean : $\mu=100$

Standard deviation : $\sigma=20$

Z-score : $z=\dfrac{x-\mu}{\sigma}$

Then, z-score corresponds to 116

$z=\dfrac{116-100}{20}=0.8$

By using the standard normal distribution table for z , we have

$P(x>116)=P(z>0.8)=1-P(z\leq0.8)$

$=1-0.7881446\approx0.2119$

Hence, the required probability = 0.2119

4 0

4 years ago

The graph represents the function f(x)=x^2+3x+2

Svetllana [295]

To reflect a function across the x axis, we want to turn all the x values that were once positive negative and vice versa. That means we want f(-x), which is: $f(x)=x^2+3x+2 \implies\\ f(-x)=(-x)^2+3(-x)+2 \implies\\ f(-x)=x^2-3x+2 =g(x)$

6 0

4 years ago

Let a,b,,c and x elements in the group G. In each of the following solve for x in terms of a,b,c, and c.

Alchen [17]

Answer with Step-by-step explanation:

We are given that a, b, c and x are elements in the group G.

We have to find the value of x in terms of a, b and c.

a. $x^2a=bxc^{-1}$

$x^2ac=bxc^{-1}c=bx$

$x^{-1}x^2ac=x^{-1}bx=b$ ( $x^{-1}bx=b$ )

$xac=b$

$xacc^{-1}=bc^{-1}$

$xa=bc^{-1}$ ( $cc^{-1}=$ )

$xaa^{-1}=bc^{-1}a^{-1}$

$x=bc^{-1}a^{-1}$

b. $acx=xac$

$acxc^{-1}=xacc^{-1}=xa$ ( $cc^{-1}=1,cxc^{-1}=x$ )

$axa^{-1}=xaa^{-1}$ ( $aa^{-1}=1,axa^{-1}=x$ )

$x=x$

Identity equation

Hence, given equation has infinite solution and satisfied for all values of a and c.

3 0

3 years ago

In a public park the number of deer doubles every year. In the year 2000, there were 25 deer in the park. The function represent

lozanna [386]

Answer:

A) 1600

Step-by-step explanation:

double the number for the first year then double that number ect untill you do six years

4 0

3 years ago