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Alexxx [7]
3 years ago
15

Jerry bought a case of 24 fancy pencils for $6.00. He sold 12 for $5.00, six for $4.00, and six for $3.50. How much was Jerry's

profit on the case of pencils?
Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0

Answer:

$6.50

Step-by-step explanation:

ehidna [41]3 years ago
5 0

Answer:

$6.50

Step-by-step explanation:

You simply add 5+6+3.5 and get 12.5 and subtract that by 6 to account for the amout he spent on the pencils.

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Is 3b-9 a algebraic expression​
Slav-nsk [51]

Answer:

yes

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1.5 &gt; 0.75x + 1 <br> what is x
motikmotik

Answer:

2/3 > x

Step-by-step explanation:

0.5 > 0.75x

2/3 > x

6 0
2 years ago
If there are n ways of completing a task, and after completing the task in any of these n ways, there are m ways of completing a
mel-nik [20]

Answer:

nm

Step-by-step explanation:

n × m = nm ways

8 0
3 years ago
What is the recursive formula for the geometric sequence with this explicit formula?
IRINA_888 [86]

For the given geometric sequence, we have:

a_1 = 9\\\\a_n = (-1/3)*a_{n-1}

So the correct option is B.

<h3>Which is the recursive formula?</h3>

Here we have the geometric sequence:

a_n = 9*(-\frac{1}{3} )^{(n - 1)}

To get the initial value of the geometric sequence, we just need to replace n by 1, so we get:

a_1 = 9*(-\frac{1}{3} )*(1 - 1) = 9

Now, notice that the common ratio is (-1/3), this means that each term of the sequence is (-1/3) times the previous term.

a_n = (-1/3)*a_{n-1}

Then the correct option is B.

If you want to learn more about geometric sequences:

brainly.com/question/1509142

#SPJ1

5 0
2 years ago
Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t
Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let \sigma_{1}^{2} be the variance for the population of weight gains for rats given a low dose, and \sigma_{2}^{2} the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2} vs H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}. We have that the sample standard deviation for n_{2} = 22 female control rats was s_{2} = 28 g and for n_{1} = 18 female low-dose rats was s_{1} = 51 g. So, we have observed the value

F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176 which comes from a F distribution with n_{1} - 1 = 18 - 1 = 17 degrees of freedom (numerator) and n_{2} - 1 = 22 - 1 = 21 degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

8 0
3 years ago
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