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I am Lyosha [343]

3 years ago

12

3/5 of my crops of peaches is damaged by hail and 3/4 of only the damaged part of the crop is sent for juicing. What fraction of

my crop is sent for juicing?

1 answer:

Sveta_85 [38]3 years ago

6 0

Answer: $\bold{\dfrac{9}{20}}$

<u>Step-by-step explanation:</u>

$\dfrac{3}{4}\quad of\quad \dfrac{3}{5}\\\\means: \dfrac{3}{4}\times \dfrac{3}{5}\quad =\dfrac{3\times 3}{4\times 5}\quad =\large\boxed{\dfrac{9}{20}}$

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Kevin wants to purchase a new car that costs $10,000. Every week he saves up $250. It has been 30 weeks. How much money does he

meriva

Kevin has $7,500 after 30 weeks. He does not have enough money for the car.

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3 years ago

The East Bay Deli, makes 12.38 pounds of pasta salad each day. West Bay Deli makes three times that amount each day. How many co

drek231 [11]

<span>The East Bay Deli, makes 12.38 pounds of pasta salad each day. West Bay Deli makes three times that amount each day. How many combined pounds of pasta salad is made per week between the two delis? Find a fourth of their combined weekly production of pasta salad.
x=12.38*7= 86.66 pounds per week
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5 0

3 years ago

What is the equation of the following graph in vertex form?

Elza [17]

$\bf \boxed{y=(x-{{ h}})^2+{{ k}}}\\\\
x=(y-{{ k}})^2+{{ h}}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
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\begin{cases}
h=4\\
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\\\\\\
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6 0

3 years ago

Read 2 more answers

About how much difference in average leaf width would you find in two forests whose average annual rainfalls are near 1500 mm bu

goblinko [34]

Answer:

4.80 mm to 2 d.p

Step-by-step explanation:

w = f(r)

f'(r) = (dw/dr) = (0.0218 mm/mm)

So, for a small difference in rainfall of 220 mm, what is the corresponding small difference in width of leaves in the two forests given.

One definition of a derivative or a rate of change is that it is the ratio of very small differences in the dependent variable to very small differences in the independent variable.

Mathematically,

(dw/dr) = (Δw/Δr) for very small Δw and Δr.

0.0218 = (Δw/220)

Δw = 0.0218 × 220 = 4.796 mm = 4.80 mm to 2 d.p

Hope this Helps!!!

5 0

3 years ago

Tower one, a cube with a hexagonal prism measures 15.6cm. Tower two, a cube with a cylinder measures 18.3cm. Tower 3, a hexagona

lina2011 [118]

Answer:

$Tower 4 = 23.9cm$

Step-by-step explanation:

Given

Tower one = 15.6 cm

Tower two = 18.3 cm

Tower 3 = 13.9 cm.

Required:

Height of the 4th tower

Represent a cube by X; a cylinder by Y and a hexagonal prism by Z

Tower one, a cube with a hexagonal prism = X + Z = 15.6

Tower two, a cube with a cylinder = X + Y = 18.3

Tower 3, a hexagonal prism with a cylinder = Z + Y = 13.9

$X + Z = 15.6$ ----- Equation 1

$X + Y = 18.3$ ----- Equation 2

$Z + Y = 13.9$ ----- Equation 3

Subtract equation 1 from 2

$(X + Y = 18.3) - (X + Z = 15.6)$

$X - X + Y - Z = 18.3 -15.6$

$Y - Z = 18.3 -15.6$

$Y - Z = 2.7$ ---- Equation 4

Add Equation 4 to Equation 3

$(Y - Z = 2.7) + (Z + Y = 13.9)$

$Y + Y - Z + Z = 2.7+ 13.9$

$2Y = 2.7+ 13.9$

$2Y = 16.6$

Divide both sides by 2

$\frac{2Y}{2} = \frac{16.6}{2}$

$Y = \frac{16.6}{2}$

$Y = 8.3cm$

Substitute $Y = 8.3cm$ in Equation 2 and 3

$X + Y = 18.3$ ----- Equation 2

$X + 8.3 = 18.3$

Subtract 8.3 from both sides

$X + 8.3 - 8.3 = 18.3 - 8.3$

$X = 18.3 - 8.3$

$X = 10cm$

$Z + Y = 13.9$ ----- Equation 3

$Z + 8.3 = 13.9$

Subtract 8.3 from both sides

$Z + 8.3 - 8.3 = 13.9 - 8.3$

$Z = 13.9 - 8.3$

$Z = 5.6cm$

So, we have that

$X = 10cm$

$Y = 8.3cm$

$Z = 5.6cm$

The question states that the 4th tower is made up of the three shapes;

This implies that;

$Tower 4 = X + Y + Z$

$Tower 4 = 10cm + 8.3cm + 5.6cm$

$Tower 4 = 23.9cm$

The height of the 4th tower is 23.9cm

8 0

3 years ago