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VikaD [51]
3 years ago
8

A food sample contains 300 bacteria. The doubling time for bacteria left at room temperature is 20 minutes. How many minutes wil

l it take to reach an unsafe level of 100000 bacteria?
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0

Answer:

167.6 minutes

Step-by-step explanation:

The formula is given as:

P(t) = Po × (2)^t/k

Where

P(t) = Population after time t = 100000

Po = Initial population = 300

k = Doubling time = 20 minutes

t = Time = ?

Hence:

100000 = 300 × (2)^t/20

Divide both sides by 300

100000/300 = (300 × (2)^t/20)/300

333.3 = 2^t/20

Take the In of both sides

In 333.3 = In (2^t/20)

In 333.3 = t/20 In 2

Divide both sides by In 2

In 333.3/In 2 =( t/20 In 2)/In 2

8.3806775072 = t/20

Cross Multiply

t = 8.3806775072 × 20

t = 167.61355014 minutes

Approximately = 167.6 minutes

Therefore, the time it will take to reach an unsafe level of 100000 bacteria is 167.6 minutes

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