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3 years ago

I need help please?!!

Mathematics

1 answer:

Helga [31]3 years ago

3 0

Answer:

Step-by-step explanation:

1+5 x 3= 16

16/2 = 8

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Find the value(s) of k such that 4x² + kx + 4 = 0 has 1 rational solution

Blababa [14]

Answer:

If you mean only one rational solution, the answer is

$k_1 = 8, k_2 = -8$

If you mean at least 1 rational solution, the answer is

$k\in (-\infty, -8]\cup[8, \infty)$

Step-by-step explanation:

$4x^2 + kx + 4 = 0$

Let's calculate the discriminant.

$\Delta = b^2 - 4ac$

$\Delta = k^2 -4 \cdot 4 \cdot 4$

$\Delta = k^2 -64$

Now, remember that:

$\text{If } \Delta > 0 : \text{2 Real solutions}$

$\text{If } \Delta = 0 : \text{1 Real solution}$

$\text{If } \Delta < 0 : \text{No Real solution}$

Therefore, I will just consider the first two cases.

$k^2 - 64 > 0$

and

$k^2 -64 = 0$

$\boxed{\text{For } k^2 - 64 > 0}$

$k^2 > 64 \Longleftrightarrow k>\pm\sqrt{64} \Longleftrightarrow k\in (-\infty, -8)\cup(8, \infty)$

$\boxed{\text{For } k^2 - 64 = 0}$

$k^2 = 64 \Longleftrightarrow k=\pm\sqrt{64} \implies k_1 = 8, k_2 = -8$

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3 years ago

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Answer:

Step-by-step explanation:

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A Minnesota man has quite a cap collection. The

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He has 19 because it wore a different cap for each hour and cups to his rip

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Problem situation:

stepladder [879]

Answer:

Rewrite so x is on the left side of the inequality.

8 + 4.99x < 20

Move all terms not containing x to the right side of the inequality.

4.99x < 12

Divide each term by 4.99 and simplify.

x < 2.405

The result can be shown in multiple forms.

Inequality Form:

x < 2.405

Interval Notation:

( −∞ , 2.405 )

Step-by-step explanation:

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2 and a half tablespoons of almond butter

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