The product of 5 and Raj’s Height is 80

<span>You only need an estimate? Great. Think of the necessary material as 6 yards, so ten costumes would take 60 yards. Then think of the fabric on hand as 240 yards, so taking 60 yards away from that would leave [an estimated] 180 yards of fabric.

For an equation, use:

F" = F' - 5.8 C

Where F' is the initial fabric stock, F" is the remaining fabric, and C is the count of costumes.

In exact numbers, the formula works out to:

F" = 238.2 - (5.8 * 10)

F" = 180.2

The estimate was very close.

Good luck.</span>

4 0

4 years ago

Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage.

ra1l [238]

Answer:

a) 0.923

b) 0.957

c) 0.88

d) 0.077

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 40

Standard Deviation, σ = 14

We are given that the distribution of number of milligrams of porphyritic per deciliter of blood is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(xis less than 60)

P(x < 60)

$P( x < 60) = P( z < \displaystyle\frac{60 - 40}{14}) = P(z < 1.4285)$

Calculation the value from standard normal z table, we have,

$P(x < 60 ) =0.923 = 92.3\%$

b) P(x is greater than 16)

$P(x > 16) = P(z > \displaystyle\frac{16-40}{14}) = P(z > -1.7142)\\\\P( z > -1.7142) = 1 - P(z \leq -1.7142)$

Calculating the value from the standard normal table we have,

$1 - 0.043 = 0.957 = 95.7\%\\P( x > 16) = 95.7\%$

c)P(x is between 16 and 60)

$P(16 \leq x \leq 60) = P(\displaystyle\frac{16 - 40}{14} \leq z \leq \displaystyle\frac{60-40}{14}) = P(-1.7142 \leq z \leq 1.4285)\\\\= P(z \leq 1.4285) - P(z < -1.7142)\\= 0.923 - 0.043= 0.88 = 88%$

$P(16 \leq x \leq 60) = 88\%$

d) P(x is more than 60)

P(x > 60) = 1 - P(x < 60) = 1 - 0.923 = 0.077

6 0

3 years ago

A culture contains 2000 bacteria initially and doubles every 40 minutes. Assuming that the rate of growth is proportional to the

Natasha2012 [34]

Answer: Hello there!

We know that the culture has 2000 bacteria initially (at t = 0 min), and it doubles when t = 40min, again at t = 80 min, and so on

And the rate of grouth is proportional to the population, then we can obtain an expression of the form:

P(t) = 2000*k(t) where k(t) is the factor that defines the growth of the population:

we know that:

p(0) = 2000*k(0) = 2000

p(40) = 2000*k(40) = 2000*2 = 4000

p(80) = 2000*k(80) = 2000*2*2 = 8000

etc

then we can see that k(t) = 2^(t/40)

where k(0) = 1, k(40) = 2, k(80) = 2*2, etc

then the function that models the population of the culture is:

p(t) = 2000*2^(t/40)

where t is in minutes.

8 0

3 years ago