Given the set of equations:
2x + y = 10
y = 3x
Let's solve for x and y.
Here, let's use substitution method.
Substitute 3x for y in equation 1:
2x + y = 10
2x + 3x = 10
5x = 10
Divide both sides by 5:
In equation 2, substitute 2 for x to find y.
y = 3x
y = 3(2)
y = 6
Therefore, we have:
x = 2 and y = 6
ANSWER:
x = 2, y = 6
SSS is 3 sides, you already know EF and DW are identical and the two triangles share side DF, so you would need to know that ED ≅ WF
Answer:
BC < CE < BE < ED < BD
Step-by-step explanation:
In the triangle BCE,
m∠BEC + m∠BCE + m∠CBE = 180°
m∠BEC + 81° + 54° = 180°
m∠BEC = 180 - 135
m∠BEC = 45°
Order of the angles from least to greatest,
m∠BEC < m∠CBE > mBCE
Sides opposite to these sides will be in the same ratio,
BC < CE < BE ----------(1)
Now in ΔBED,
m∠BEC + m∠BED = 180°
m∠BED = 180 - 45
= 135°
Now, m∠BDE + m∠BED + DBE = 180°
11° + 135°+ m∠DBE = 180°
m∠DBE = 180 - 146
= 34°
Order of the angles from least to greatest will be,
∠BDE < ∠DBE < ∠BED
Sides opposite to these angles will be in the same order.
BE < ED < BD ----------(2)
From relation (1) and (2),
BC < CE < BE < ED < BD
4 divided by 3 = a whole and 3 repeated more than 4 times
(to use the number 4)
:D
Answer:
13
Step-by-step explanation:
To solve this, lets first find the number of footballs he still needs:
75-24 = 51
Now to find the number of packages, divide by 4, since there are 4 balls per package:
51/4 = 12 Remainder 3
Since there is a remainder, and the Coach MUST have at least 75, then we need to add a package to include the remainder:
12 + 1 = 13 Packages
