Distribute 2 and remove parentheses :
1/2x+8=3x-6
Multiply both sides of equation by 2:
x+16=6x-12
Move terms:
x+16-6x=-12
x-6x=-12-16
Collect like terms:
-5x=-28
Divide both sides:
x=28/5
The 7 after the decimal is in the tenths place, so look at the one in the hundredths place. It is less than 5, so the 7 is not rounded up and stays 7. 877.7 is 877.71 rounded to the nearest tenth.
I took this test the other day I put figure 2 and I got it right
The second-degree polynomial function f(x) that has a lead coefficient of 4 and roots 5 and 2 is f(x) = 4x² -28x + 40. The correct option is the last option f(x)=4x²-28x+40
<h3>Quadratic equation</h3>
From the question, we are to determine which second-degree polynomial function f(x) has a lead coefficient of 4 and roots 5 and 2
To determine this, we will use the given roots to determine the equation
The roots are 5 and 2
Thus
x = 5 and x = 2
x - 5 = 0 and x - 2 = 0
Therefore,
(x -5)(x -2) = 0
Distributing
x(x -2) -5(x -2) = 0
x² -2x -5x + 10 = 0
x² -7x + 10 = 0
Now, multiplying through by 4, we get
4x² -28x + 40 = 0
Thus, the function becomes f(x) = 4x² -28x + 40
Hence, the second-degree polynomial function f(x) that has a lead coefficient of 4 and roots 5 and 2 is f(x) = 4x² -28x + 40. The correct option is the last option f(x)=4x²-28x+40
Learn more on Quadratic Equation here: brainly.com/question/19257086
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