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Ivenika [448]
3 years ago
10

I need help hdbcjsjfnfnfjfjffdbbfdncndnc

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0
\frac{3}{15k+30} : \frac{6k}{5k^2+30k+40} = \frac{3}{15(k+2)} . \frac{5(k+2)(k+4)}{6k} = \frac{k+4}{6k}
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What numbers has a line of symmetry
tia_tia [17]
For digits 0 to 9 
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8 0
3 years ago
Given the quantic solve for x . 2x⁵-6x³-4x²+2x+4​
Eva8 [605]
This problem cannot be done because it is not an equation meaning it does not have an “=“
4 0
2 years ago
Find the H.C.F of the following expressions.{x²-3x,x²-9}​
lora16 [44]

Answer:

x2−3x+2=x2−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x2−4x+3=x2−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)

Thus, the only common factor is (x-1)

Option A

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6 0
3 years ago
Read 2 more answers
For each of the following vector fields
olga nikolaevna [1]

(A)

\dfrac{\partial f}{\partial x}=-16x+2y

\implies f(x,y)=-8x^2+2xy+g(y)

\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y

\implies\dfrac{\mathrm dg}{\mathrm dy}=10y

\implies g(y)=5y^2+C

\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}

(B)

\dfrac{\partial f}{\partial x}=-8y

\implies f(x,y)=-8xy+g(y)

\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x

\implies \dfrac{\mathrm dg}{\mathrm dy}=x

But we assume g(y) is a function of y alone, so there is not potential function here.

(C)

\dfrac{\partial f}{\partial x}=-8\sin y

\implies f(x,y)=-8x\sin y+g(x,y)

\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y

\implies\dfrac{\mathrm dg}{\mathrm dy}=4y

\implies g(y)=2y^2+C

\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}

For (A) and (C), we have f(0,0)=0, which makes C=0 for both.

4 0
3 years ago
Hello I have uploaded the question via image
maksim [4K]
Labour. They are man-made and used in agriculture.
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2 years ago
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