Answer:
Yes. No graph paper.
Step-by-step explanation:
Let's say the 3 points are A, B, C.
If A, B and C lie on one line then ![m_{AB} = m_{BC} = m_{AC}](https://tex.z-dn.net/?f=m_%7BAB%7D%20%3D%20m_%7BBC%7D%20%3D%20m_%7BAC%7D)
![m_{AB} = \frac{y_{B}-y_{A} }{x_{B}-x_{A}} = \frac{2-6}{3-5} = \frac{-4}{-2} = 2\\m_{BC} = \frac{y_{C}-y_{B} }{x_{C}-x_{B}} = \frac{8-2}{6-3} = \frac{6}{3} = 2\\\\m_{AC} = \frac{y_{C}-y_{A} }{x_{C}-x_{A}} = \frac{8-6}{6-5} = \frac{2}{1} = 2\\\\](https://tex.z-dn.net/?f=m_%7BAB%7D%20%3D%20%5Cfrac%7By_%7BB%7D-y_%7BA%7D%20%7D%7Bx_%7BB%7D-x_%7BA%7D%7D%20%3D%20%5Cfrac%7B2-6%7D%7B3-5%7D%20%3D%20%5Cfrac%7B-4%7D%7B-2%7D%20%3D%202%5C%5Cm_%7BBC%7D%20%3D%20%5Cfrac%7By_%7BC%7D-y_%7BB%7D%20%7D%7Bx_%7BC%7D-x_%7BB%7D%7D%20%3D%20%5Cfrac%7B8-2%7D%7B6-3%7D%20%3D%20%5Cfrac%7B6%7D%7B3%7D%20%3D%202%5C%5C%5C%5Cm_%7BAC%7D%20%3D%20%5Cfrac%7By_%7BC%7D-y_%7BA%7D%20%7D%7Bx_%7BC%7D-x_%7BA%7D%7D%20%3D%20%5Cfrac%7B8-6%7D%7B6-5%7D%20%3D%20%5Cfrac%7B2%7D%7B1%7D%20%3D%202%5C%5C%5C%5C)
Hence, they lie on one line.
You don't need to use a graph paper to prove it.
Answer:
The divisor and dividend have the same signs.
Step-by-step explanation:
Let's look at all of the possible outcomes of dividing with different signs.
Positive / positive = positive
Positive / negative = negative
Negative / positive = negative
Negative / negative = positive
We can see that whenever the signs are the same, the quotient is positive.
Answer:
30y+14
Step-by-step explanation:
add the values of all the sides together: (5y+4) + (5y+4) + (10y+3) + (10y+3) = (5y + 5y + 10y + 10y) + (4 + 4 + 3 + 3)= 30y + 14
Answer:
A= 40°
B= 35°
C= 15°
Step-by-step explanation:
Since it says if the triangles were accurately drawn, then A would be the same degree as Q. C would be the same degree as P. B would be the same degree as R. Since R's degree is missing I knew that a obtuse triangle was 90°. I added 40+15 and got 55. Then i subtracted 90-55 and got 35. So the unknown value would be 35°.
I hope this helps.
The last one because a perpendicular triangle would be drawn from the vertice to the bottom.