Answer:
A
Step-by-step explanation:
|((experimental - theoretical) / theoretical)| x 100
5.5 - 5.62 / 5.62 = -.0213
|-.0213| = .0213
.0213 x 100 = 2.13
 
        
             
        
        
        
Answer:
x3 – 7x2 + 3------  x3 - 7x2 + 3
 3x3 + x2-----------x2 • (3x + 1)
x2 + 4x - 3------------ x2 + 4x - 3
Step-by-step explanation:
Step  1  :
Equation at the end of step  1  :
  ((x3) -  7x2) +  3
Step  2  :
Polynomial Roots Calculator :
 2.1    Find roots (zeroes) of :       F(x) = x3-7x2+3
Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient
In this case, the Leading Coefficient is  1  and the Trailing Constant is  3.
 The factor(s) are:
of the Leading Coefficient :  1
 of the Trailing Constant :  1 ,3
 Let us test ....
  	P    Q    P/Q    F(P/Q)    	Divisor
      -1       1        -1.00        -5.00      
      -3       1        -3.00        -87.00      
      1       1        1.00        -3.00      
      3       1        3.00        -33.00    
Hope this helps.	
 
        
                    
             
        
        
        
Answer:
f(8) = 195
Step-by-step explanation:
When the x if f(x) is replaced with an 8, this just means that it is the eighth term. All you really have to do is replace every X in the function to find the answer.
f(8) = 3 + 3(8)²
f(8) = 3 + 3(64)
f(8) = 3 + 192
f(8) = 195
Hope this helps!
 
        
                    
             
        
        
        
Answer:
x = 6 months.
The equation is given by $45 + ($49.45 × x) = ($56.95 × x).
Step-by-step explanation:
i) Let x be the number of months of Internet Service purchased till the Fast 
   Internet charges and Quick Internet charges become the same.
ii) Charges for Fast Internet for x months is given by $45 + ($49.45 × x)
iii) Charges for Quick Internet for x months is given by ($56.95 × x)
iv) According to the first statement we will now equate the equations in ii)  
    and iii) and solve for x.
    Therefore, $45 + ($49.45 × x) = ($56.95 × x)
                       45 + 49.45 x  =  56.95 x
   Therefore  (56.95 - 49.45) x = 45
                     7.50 × x  =  45
   Therefore x = 45 ÷  7.5 = 6