Question

Explain the answer because im stuck

Answer 1

Answer:

The Proof is given below.

Step-by-step explanation:

Given:

$\overline{HF}$  bisect ∠ EHG.i.e

∴ ∠EHF ≅ ∠ GHF

$\overline{EH} \cong \overline{GH}$  

To Prove:

$\overline{EF} \cong \overline{GF}$  

Proof:

In  Δ EHF and Δ GHF

    EH ≅ GH     ………............{Given}

∠ EHF ≅ ∠ GHF     …………..{EF bisect ∠ EHG as given above}

     HF ≅ HF     ………............{Reflexive Property}

Δ EHF ≅ Δ GHF …................{ By Side-Angle-Side test}

∴ EF ≅ GF........{corresponding parts of congruent triangles (c.p.c.t).}

$\overline{EF} \cong \overline{GF}$  ....... PROVED