When we toss a penny, experience shows that the probability (long term proportion) of a head is close to 1-in-2. suppose now tha
t we toss the penny repeatedly until we get a head. what is the probability that the first head comes up in an odd number of tosses (one, three, five, and so on)?
This is a sum of an infinite series problem.
A sequence of 1 will happen with a probability of 0.5
A sequence of 3 will happen with a probability of 1/2^3, 1/8, = 0.125
In general we have an infinite series of
1/2^1 + 1/2^3 + 1/2^5 + ... + 1/2^(2n-1) where n >= 1
The sum of such a series with a constant ratio between sequential terms is
S = s1/(1-r)
where
s1 = first term in the series
r = ratio between terms.
The value for s1 = 0.5 as shown above and the 2nd term is 0.125. So
r = 0.125 / 0.5 = 0.25
And the sum of the infinite series is
S = s1/(1-r)
S = 0.5/(1 - 0.25)
S = 0.5/0.75
S = 2/3
S = 0.666..66
So the probability of the first head coming up in an odd number of tosses is 2/3, or 66.6%</span>
