Answer:
You don't even need to do the whole question. Just look at 5 times 2x. which is 10x then u get your answer
Step-by-step explanation:
without seeing a picture I'm guessing 45 45, and 90
The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
8x-5=19
+5 on each side
8x=24
Divide by 8 on each side.
X=3
Answer:
Step-by-step explanation:
Given the expressions all that is required is to expand them (using the distributive property) to see which answers they match up to:
For a: 
For b: 
For c calculate the square of a sum: 
(add like terms) c: 
For d: 
