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2 years ago

Prime factorization of 675 using exponents

Mathematics

1 answer:

r-ruslan [8.4K]2 years ago

8 0

So
5*5*3*3*3=5²*3³

Prime factorization is 5²*3³

Answer=5²*3³

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I NEED HELP ASAP PLEASE!!!!

givi [52]

Answer:

Hello!

An irrational number is all the real numbers which are not rational numbers.

M = $\sqrt{2$ is a irrational number.

N = $\sqrt{5}$ is a irrational number.

S = 2 is not irrational, and is actually a whole number.

T = 5 is not irrational, and is actually a whole number.

Have a great day!

I hope this helps! <33

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2 years ago

Determine the area of the triangle.

coldgirl [10]

Answer:

396.8

Step-by-step explanation:

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3 years ago

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Explain how to compute the amount of money the worker receives for any

BARSIC [14]

Answer:

its 11

Step-by-step explanation:

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8 0

2 years ago

Slope = 4, passing through (-6, 8)

Mademuasel [1]

The point slope form is y - 8 = 4(x + 6) and the slope intercept form would be y = 4x + 32.

In order to find this, we'll start with the base form of point-slope form.

y - y1 = m(x - x1) ----> Plug in the numbers

y - 8 = 4(x - -6) ----> Simplify

y - 8 = 4(x + 6)

Now to find slope intercept form, solve for y.

y - 8 = 4(x + 6) ----> distribute the 4

y - 8 = 4x + 24 -----> add 8 to both sides

y = 4x + 32

7 0

2 years ago

Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

<em>Hence, the smallest sum is 2</em>

3 0

3 years ago