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GrogVix [38]
3 years ago
5

In a survey of college​ students,894 said that they have cheated on an exam and 1701 said that they have not. If one college stu

dent is selected at​ random, find the probability that the student has cheated on an exam.
Mathematics
1 answer:
iren [92.7K]3 years ago
6 0
Need to know more hkjhklaqhjwd

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What is the answers and how do u get those answers
Arada [10]
Question 5 and 7 only?
6 0
3 years ago
F(4g2-9)=n i need to solve for f
meriva

Answer:

Step-by-step explanation:

6 0
2 years ago
3. Three years ago, Jane was three times as old as Alice. In two years time, the sum of their ages will be 62. Determine their p
anzhelika [568]
3 yrs ago:

Alice - x 
Jane - 3x 

Fast forward 2 years... 1 year ago: 

Sum of their ages = 62


Equation to solve: x + 3x = 62 
                                4x = 62 
                               -----  -----
                                 4      4
 
                                 x = 15.5 

From this, we can deterime that Alice is 15 1/2 years old. 

Then, plug in 15.5 for x in 3x to find Jane's age. 

15.5 × 3 = 46.5

From this, we can determine that Jane is 46 1/2 years old. 


I hope this helps you to understand this problem better.


5 0
3 years ago
Read 2 more answers
Can someone please explain this to me please? Thank you : )
Ber [7]

Answer:

7/25

Step-by-step explanation:

if 7% are defective and they order 25% of their lightbulbs from Baker that will be your answer.

6 0
3 years ago
Given:
Goryan [66]

Answer:

a.Converge

b.Diverge

Step-by-step explanation:

We are given that

A_n=\frac{6n}{-4n+9}

\lim_{n\rightarrow \infty}A_n=\lim_{n\rightarrow \infty}\frac{6n}{-4n+9}=\frac{6n}{n(-4+\frac{9}{n})}

\lim_{n\rightarrow \infty}\frac{6}{-4+\frac{9}{n}}=\frac{6}{-4}=\frac{-3}{2}

Because \frac{9}{\infty}=0

Hence, sequence An converges to \frac{-3}{2} when n tends to infinity or - infinity.

\sum_{n=1}^{\infty}An=\sum_{n=1}^{\infty}\frac{6n}{-4n+9}=diverges

Necessary condition for a series to converge :

an\rightarrow 0 when n tends to infinity .

But A_n tends to \frac{-3}{2}when n tends to infinity.

Therefore, given series is divergent.

5 0
3 years ago
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