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GrogVix [38]
3 years ago
5

In a survey of college​ students,894 said that they have cheated on an exam and 1701 said that they have not. If one college stu

dent is selected at​ random, find the probability that the student has cheated on an exam.
Mathematics
1 answer:
iren [92.7K]3 years ago
6 0
Need to know more hkjhklaqhjwd

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Consider the equation below.
Eduardwww [97]

Answer:

The equation has no solutions .

Step-by-step explanation:

Given as :

<u>The linear equation is </u>

\dfrac{3}{4}(24 -16 x) = \dfrac{-2}{3}(18 x -27)

Or, \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x -  \dfrac{-2}{3} × 27

Or,  \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x + \dfrac{2}{3} × 27

Or, \frac{3\times 24}{4} -  \frac{3\times 16 x}{4} =  \frac{-2\times 18 x}{3} + \frac{2\times 27 x}{3}

Or, 3 × 6 - 3 × 4 x = - 2 × 6 x + 2 × 9

Or, 18 - 12 x = - 12 x + 18

Or, 18 - 18 = - 12 x + 12 x

or, 0 = 0

∵ The linear equation has no variables , so the equation has no solution

Hence,The equation has no solutions . Answer

8 0
2 years ago
A coin will be flipped three times. The result of each flip is either heads (H) or tails (T). The outcome HTH represents the fir
Yuki888 [10]
The answer is 4/7
Welcome x
3 0
2 years ago
Find the zeros and verify x^2 +2x-180
Arada [10]

Answer:

Rounded to the nearest tenth they are -14.5 and 12.5

Step-by-step explanation:

The zeros of a function are the x-intercepts or roots where the function crosses the x-axis. To find them, graph the function x^2 +2x-180 and zoom in on the x-axis.

See attached picture.

6 0
3 years ago
Convert 3 18/25 to a decimal using long division.
zaharov [31]
Change into improper fraction 
take 3 x 25+18 divided by 25=93\25
93\25=3.72
3 0
3 years ago
The vertices of a parallelogram are at (-9, 12), (-3, 12), (-5, 10), and (–11, 10). What is the perimeter of the parallelogram?
eduard

let point A has coordinates (-9;12),B(-3;12),C(-5;10) and D(-11;10).Then the vector AB={6;0}, BC={2;-2}, CD={6;0}, AD={2;-2} and their and the length of the vectors

|AB| = |CD| = \sqrt{ {6}^{2} + {0}^{2} } = \sqrt{36} = 6 \\ |BC| = |AD| = \sqrt{ {2}^{2} + {( - 2)}^{2} } = \sqrt{8}

p = 6 + 6 + \sqrt{8} + \sqrt{8} = \\ = 12 + 2 \sqrt{8} = 17.66\approx18

7 0
3 years ago
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