Octogon
sides=4
draw lines from the outside angles to the center so they form 8 equal triangle sections
find the area of each triangle and multiply by 8
area of triangle=1/2 base times height
base=4
the height is the distance from the center of one side of the octogon, to the center=5
so area=4 times 1/2 times 5=4 times 5=10
8 triangles so 8 times 10=80
the answer is 80cm^2
the diagram included below shows area for a pentagon
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team D lost 3 times... if not then maybe 1 idk my brain hurts
What are you talking about?
Answer:
b= -3
x= -2
x= -7
n = -6
Step-by-step explanation:
3b+7-1=-3
3b = -3 -7 +1
3b = -10+1
3b= -9
b = -9/3
b= -3
3x+1-6x=7
-3x = 7-1
-3x= 6
x= -6/3
x= -2
312=-6(7x-3)
312 = -6*7x +6*3
312= -42x +18
312-18= -42x
294 = -42x
x= -294/42
x= -7
-4(4n-8)=128
-4*4n +4*8 =128
-16n +32 = 128
-16n= 128-32
-16n = 96
n=-96/16
n = -6