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-Dominant- [34]
3 years ago
15

Suppose the life span of a calculator has a normal distribution with a mean of 60 months and a standard deviation of 8 months. W

hat is the probability that the calculator works properly for 74 months or more
Mathematics
1 answer:
rusak2 [61]3 years ago
7 0

Answer:

Probability that the calculator works properly for 74 months or more is 0.04 or 4%.

Step-by-step explanation:

We are given that the life span of a calculator has a normal distribution with a mean of 60 months and a standard deviation of 8 months.

Firstly, Let X = life span of a calculator

The z score probability distribution for is given by;

         Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 60 months

            \sigma = standard deviation = 8 months

Probability that the calculator works properly for 74 months or more is given by = P(X \geq 74 months)

     P(X \geq 74) = P( \frac{ X - \mu}{\sigma} \geq \frac{74-60}{8} ) = P(Z \geq 1.75) = 1 - P(Z < 1.75)

                                                   = 1 - 0.95994 = 0.04

Therefore, probability that the calculator works properly for 74 months or more is 0.04 or 4%.

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Answer:

​  Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

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Step by step solution :

STEP

1

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Equation at the end of step 1

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STEP

2

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STEP

3

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Pulling out like terms

3.1     Pull out like factors :

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Trying to factor by splitting the middle term

3.2     Factoring  12e2 + 267e + 4  

The first term is,  12e2  its coefficient is  12 .

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Step-1 : Multiply the coefficient of the first term by the constant   12 • 4 = 48  

Step-2 : Find two factors of  48  whose sum equals the coefficient of the middle term, which is   267 .

Step-by-step explanation:

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