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-Dominant- [34]
3 years ago
15

Suppose the life span of a calculator has a normal distribution with a mean of 60 months and a standard deviation of 8 months. W

hat is the probability that the calculator works properly for 74 months or more
Mathematics
1 answer:
rusak2 [61]3 years ago
7 0

Answer:

Probability that the calculator works properly for 74 months or more is 0.04 or 4%.

Step-by-step explanation:

We are given that the life span of a calculator has a normal distribution with a mean of 60 months and a standard deviation of 8 months.

Firstly, Let X = life span of a calculator

The z score probability distribution for is given by;

         Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 60 months

            \sigma = standard deviation = 8 months

Probability that the calculator works properly for 74 months or more is given by = P(X \geq 74 months)

     P(X \geq 74) = P( \frac{ X - \mu}{\sigma} \geq \frac{74-60}{8} ) = P(Z \geq 1.75) = 1 - P(Z < 1.75)

                                                   = 1 - 0.95994 = 0.04

Therefore, probability that the calculator works properly for 74 months or more is 0.04 or 4%.

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2 years ago
In Juan's coin bank there are nickels (n),
alukav5142 [94]

Answer:

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Step-by-step explanation:

  1. First, the equation would be (2/4d) x 5 +d x 10 +1/4d x 25= 600 (Don't put 6.00, that's dollars. We put 6 dollars into cents to make it easier.)
  2. Then we slowly start to solve: 10/4d + 10d + 25/4d = 600
  3. 10d+40d+25d/4 = 600 (Put all of that over 4, not first 25d)
  4. 75d= 600 x 4
  5. d=600 x 4/75 (same here put everything over 75)
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Answer:

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Step-by-step explanation:

Hope that helps.

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