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3 years ago

PLEASE HELP!!!!!!!!!!!!!!

Mathematics

1 answer:

mr_godi [17]3 years ago

5 0

27 cubic feet.

You can get this because the surface area formula shows that each edge is 3ft. the area would be length x width x height, which are all 3.

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An ice-skating competition lasted three days. Day one had an attendance of 16,390 people. Day two had an attendance of 16,550 pe

lana [24]

Answer:

$Day\ 3 = 16237$

$Day\ 1 = 16390$

$Day\ 2 = 16550$

Step-by-step explanation:

Given

$Day\ 1 = 16390$

$Day\ 2 = 16550$

$Day\ 3 = 16237$

Required

Order from least to greatest

Comparing 16390, 16550 and 16237.

The order of arrangement from least to greatest is:

16327, 16390 and 16550.

So, we have:

$Day\ 3 = 16237$

$Day\ 1 = 16390$

$Day\ 2 = 16550$

6 0

3 years ago

7/4x-5 + 2y - 3.5 + -1/4x + 5

romanna [79]

-7/4+2y+1/4x is the answer

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2 years ago

What is the area of the region bounded between the curves y=x and y=sqrt(x)?

erastova [34]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

y = x .....(1)

$y=\sqrt{x}$ .... (2)

By solving equation (1) and equation (2)

$x = \sqrt{x}$

$\sqrt{x}\left ( \sqrt{x}-1 \right )=0$

$\sqrt{x}=0$ or $\left ( \sqrt{x}-1 \right )=0$

x = 0, x = 1

y = 0, y = 1

A = $\int_{0}^{1}ydx(curve)-\int_{0}^{1}ydx(line)$

A = $\int_{0}^{1}\sqrt{x}dx-\int_{0}^{1}xdx$

A = $\frac{2}{3}[x^\frac{3}{2}]_{0}^{1}-\frac{1}{2}[x^2]_{0}^{1}$

A = $\frac{2}{3}-\frac{1}{2}$

A = $\frac{1}{6}$

8 0

2 years ago

The events committee buys 100 flowers for a school dance the flowers are a combination of carnations an roses. Each carnation co

Natali5045456 [20]

Answer:

We don't know the price of the roses, so there is not enough information to answer.

6 0

2 years ago

What percent is 25 is 4 plz help

andrew11 [14]

Answer: 16%

Step-by-step explanation:

4:25*100 =

(4*100):25 =

400:25 = 16

6 0

3 years ago