Answer:
I used an Excel spreadsheet to calculate R² which gives us the least squares trend. See attached image.
y = 360x + 1600
R² = 0,9529
next year's enrollment should be = (360 x 5) + 1600 = 3400
Answer:
Explanation:
1. Mineral mine - $9.3 million
Development costs - $2500 000
1/[(1+0.07)^4]=0.76290
Restoration costs = $472995 = [(530k * 0.4)+(630k * 0.3)+($730k * 0.3)] *0.76290
Cost of mine= $9.3 million+$2500 000+$472995 = $12272995
2. Depletion:
($12272995/730000tons)*113000tons=$1899792
Depreciation of machinery=($143400-$12000)/730000 * 113000tons = $20340
Depreciation of structures=($36500/730000tons)*113000tons=$5650
3. Accrecion expense recognized:
$472995*0.07*8/12=$22073