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velikii [3]
2 years ago
5

What's the following sequence

Mathematics
2 answers:
Dmitry [639]2 years ago
8 0
Your answer is A !! go for it !!
s344n2d4d5 [400]2 years ago
7 0
A because it follows the geometric sequence formula
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Substitute x=y+1 into the expression 3x -1 and determine the first step
Kruka [31]

Answer: the solution becomes 3=y+1-1

Step-by-step explanation:

The first step is to combine like terms meaning you subtract 1-1. Then you are left with 3=y.

8 0
3 years ago
Use the line plot above to answer all 4 questions. Label your responses (a), (b), (c), and (d). When asked to explain you must u
mojhsa [17]
A) it is left skewed
B) the median is 5
C) the mean is 5.15
D) the mean would be more affected (a change of 1.05 versus a change of 0.5).

The majority of the data is to the right of the graph; this means it is left skewed.

To find the median, write all of the data values out:
2, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7

The middle value is 5.

We find the sum of this set of values and divide by 13, the number of data points, to find the mean:
2+3+4+4+5+5+5+6+6+6+7+7+7 = 67/13 = 5.15

If we added an additional data value at 20, the new median would be 5.5.  The new mean would be (67+20)/14 = 6.2.  The mean changes more than the median.
4 0
2 years ago
How to solve X^4-19x^2+48=0
ZanzabumX [31]
Two numbers that add up to -19 and multiply to 48 are -16 and -3:

(x^4-19x^2+48)=0\\(x^2-16)(x^2-3)=0\\(x+4)(x-4)(x^2-3)=0

So, the solutions come from each parentheses:  x+4=0, x-4=0, and x^2-3=0.

x+4=0
x = -4

x-4=0
x = 4

x^2-3=0
x^2 = 3
x = +/- √3

So, the solutions are -4, -√3, √3, and 4.
4 0
3 years ago
Look at the graph shown below:
ElenaW [278]
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 0}}\quad ,&{{ 4}})\quad 
%   (c,d)
&({{ -4}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-4}{-4-0}

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=0\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}

once you get the slope and solve for "y", that'd be the equation of the line.
7 0
2 years ago
PLEASE HELP ILL GIVE YOU BRAINLEST
Sergio [31]

Answer:

The absolute value is the distance between a number and zero.

5 0
3 years ago
Read 2 more answers
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