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3 years ago

The height of a cone is two times its base diameter. What is the volume of the cone in terms of its base radius r?

Mathematics

1 answer:

nydimaria [60]3 years ago

5 0

Volume of the cone = (1/3) pi r^2 h

h = 2r so substituting for h:-

V = (1/3) pi r^2 * 2r

V = (2/3) pi r^3

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Nancy's Cupcakes recorded how many cupcakes it recently sold of each flavor.

Alexeev081 [22]

Answer:

pumpkin because it got the most sold

7 0

2 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

Mary had a 3-inch piece of ribbon. She cut it in half. How long were they new pieces

allochka39001 [22]

Answer:

1 and a half inches long

Because that 3 divided by 2 is 1.5.

7 0

3 years ago

Read 2 more answers

Jason wanted to buy postcards for his cousin. The price was 2 cards for $1. He had some change in his pocket. What combination o

Zina [86]

Answer:

2 dimes, 1 nickel and 3 quarters.

Step-by-step explanation:

The price of 2 postcards is $1. Any combination of coins that adds to $1 will work here. Remember, a penny is worth 0.01, a nickel is worth 0.05, a dime is worth 0.10, and a quarter is worth 0.25.

Adding 2 dimes, 1 nickel, and 3 quarters would be 2(0.10)+1(0.05)+3(0.25)=1.

8 0

3 years ago

Researchers would like to test if the mean bone mineral density is different for the three different groups. Conduct an ANOVA te

laiz [17]

Answer:

H₀: μ₁ = μ₂= μ₃

Hₐ: At least one of the means is different.

Step-by-step explanation:

Analysis of variance or ANOVA test is used to determine whether the means of different groups are similar or not.

The hypothesis of an ANOVA test for n homogeneous groups is:

$H_{0}: \mu_{1}= \mu_{2}= \mu_{3}...= \mu_{n}\\H_{a}: At\ least\ one\ of\ the\ means\ is\ different$

In this case the researcher is testing whether the mean bone mineral density is different for the three different groups.

The hypothesis for this test can be defined as follows:

H₀: The mean bone mineral density is not different for the three different groups, i.e. μ₁ = μ₂= μ₃

Hₐ: The mean bone mineral density is different for the three different groups, i.e. at least one of the means is different.

3 0

3 years ago