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BlackZzzverrR [31]
3 years ago
12

A. {0,1,2,3,4} B. {1,2,3,4} C. {-1,0,1,2,3} D. {-2,-1,0,1,2,3,4}

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0

Option D:

The set is {-2, -1, 0, 1, 2, 3, 4}.

Solution:

Given set:

\{x \in Z:-2 \leq x \leq 4\}

Z means integer values.

Integer means set of positive and negative values including zero.

-2 \leq x \leq 4

This means x lies between -2 and 4.

  • If x strictly less than -2 and greater than 4 means you don't have to include -2 and 4.
  • But here x less than or equal to -2 and greater than or equal to 4, so you have to include -2 and 4.

The integers are -2, -1, 0, 1, 2, 3 and 4.

So, x belongs to the set {-2, -1, 0, 1, 2, 3, 4}

Hence the given set is defined by the set  {-2, -1, 0, 1, 2, 3, 4}.

Option D is the correct answer.

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A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below: The f
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The following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

To answer the question, we need to know what volume is.

<h3>What is volume?</h3>

This is the capacity of a material or container.

Since the silo is made of a cylindrical and a conical part, we need to find the volume of both parts.

<h3>Volume of cylindrical part.</h3>

So, the volume of the cylindrical part V = πr²h where

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  • h = length of cylindrical part = 8 ft.

So, V = πr²h

V = π(2 ft)²8 ft

<h3>Volume of the conical part</h3>

The volume of the conical part is given by V' = 1/3πr²h where

  • r = radius of cone = 2ft and
  • h = height of cone.

Since the entire length of silo is 9.5 ft and length of cylindrical part is 8 ft, then the height of cone is h' = 9.5 ft - 8 ft

So, V' = 1/3πr²h'

V' = 1/3π(2 ft)²(9.5 ft - 8ft)

<h3>Total volume of grains in silo</h3>

The total volume of grains equals the total volume of the silo V" = V + V'

V" = π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

So, the following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

Learn more about volume here:

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2 years ago
Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).
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The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

  • x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
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So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

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  • (h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

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<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

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