1 Chicken have = 2 legs
1 Cow have = 4 legs
No of cows = x
No of chickens = y
Total no of legs = 4x + 2y = 210.............(1)
Total No of heads = x + y = 84................(2)
x = 84 - y....( from (2) )
Substituting the above equation in (1)
4 ( 84 - y) + 2y = 210
336 - 4y + 2y = 210
336 - 2y = 210
-2y = -126
= y = 63
No of cows = 84-63 = 21
∴ <u><em>Total no of cows = 21</em></u>
<u><em>Total no of chickens = 63</em></u>
Answer:
Same-side Interior Angles theorem justifies ∠ 11 + ∠ 10 =180°
Step-by-step explanation:
To Prove:
∠ 11 + ∠ 10 =180°
Proof:
Consider lines are Parallel,then
Corresponding Angles are Equal
∴ ∠ 10 = ∠ 12 say (equation 1)
Now by Linear Pair postulate we have,
∴ ∠ 11 + ∠ 12 = 180° say (equation 2)
Now by replacing ∠12 by ∠ 10 from equation 1 in equation 2 we get
∴ ∠ 11 + ∠ 10 = 180°
Hence proved the above statement.
Answer:
No solution
Step-by-step explanation:
So first we have to Distribute;
-3x + 3 > -3x - 2
This is an solution which means that they can never intersect on a graph.
We can solve further if you want;
Add 3x to both sides;
The x cancel themselves out.
3 > -2
Answer:
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected individual will be between 185 and 190 pounds?
This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So
X = 190



has a pvalue of 0.8944
X = 185



has a pvalue of 0.7357
0.8944 - 0.7357 = 0.1587
15.87% probability that a randomly selected individual will be between 185 and 190 pounds