Answer:
yes
Step-by-step explanation:
Answer:
The answer to your question is below
Step-by-step explanation:
Functions
f(x) = 12x f⁻¹(x) = 2x
a) f⁻¹(-2) = 2(-2)
f⁻¹(-2) = -4
b) f(-4) = 12x
f(-4) = 12(-4)
f(-4) = -48
c) f(f⁻¹(-2)) =
f(f⁻¹(x)) = 12(2x) = 24x
f(f⁻¹(-2)) = 24(-2) = -48
I think your functions are wrong they must be f(x) = 1/2x f⁻¹(x) = 2x
a) f⁻¹(-2) = 2(-2)
= -4
b) f(-4) = 1/2(-4)
= -2
c) f(f⁻¹(x)) = 1/2(2x)
= x
f(f⁻¹(-2)) = -2
Answer:
Alexander is incorrect because the expressions are not equivalent.
Step-by-step explanation:
If the expression is evaluated for any value of x, y; the result will not be same.
For instance, let assume x = 1 and y = 2
3x + 4y = 3 + 4 = 7
(3)(4) + xy = (3)(4) + (1 * 2) = 12 + 2 = 14
So, the expressions are not the same and Alexander is incorrect.
