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3 years ago

Sec (90 -A) sinA = cot (90-A). tan( 90- A)

Mathematics

2 answers:

Lapatulllka [165]3 years ago

8 0

L.H.S=sec(90-A)·sinA

=cosecA·sinA ;[sec(90-A)= cosecA]

=1/sinA·sinA ;[cosecA=1/sinA]

R.H.S=cot(90-A)·tan(90-A)

=tanA·cotA ;[cot(90-A)=tanA, tan(90-A)=cotA]

=tanA·1/tanA ;[cotA=1/tanA]

thus, L.H.S=R.H.S

[Proved]

djyliett [7]3 years ago

3 0

Step-by-step explanation:

sec(90-A) . Sin A = cot (90-A) . tan(90-A)

cosec X sinA = tanA X cotA

1/sinA X sinA = tanA X 1/tanA

1=1

Hence proved

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Sec (90 -A) sinA = cot (90-A). tan( 90- A)​

Sec (90 -A) sinA = cot (90-A). tan( 90- A)