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koban [17]
3 years ago
6

Sec (90 -A) sinA = cot (90-A). tan( 90- A)​

Mathematics
2 answers:
Lapatulllka [165]3 years ago
8 0

L.H.S=sec(90-A)·sinA

        =cosecA·sinA ;[sec(90-A)= cosecA]

        =1/sinA·sinA ;[cosecA=1/sinA]

        =1

R.H.S=cot(90-A)·tan(90-A)

        =tanA·cotA ;[cot(90-A)=tanA, tan(90-A)=cotA]

        =tanA·1/tanA ;[cotA=1/tanA]

        =1

thus, L.H.S=R.H.S

[Proved]

djyliett [7]3 years ago
3 0

Step-by-step explanation:

sec(90-A) . Sin A = cot (90-A) . tan(90-A)

cosec X sinA = tanA X cotA

1/sinA X sinA = tanA X 1/tanA

1=1

Hence proved

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3 years ago
Function Q gives a puppy's weight in pounds as function of its age in months. What does each expression represent in this situat
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Answer:

Q(18) is a mathematical representation of the weight in pounds of a puppy after 18 months.

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Step-by-step explanation:

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Q(18)

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Function Q gives a puppy's weight in pounds as function of its age in months

What does each expression represent in this situation?

A function is generally represented in the form a(x) ;

Hence, Q(18) is a mathematical representation of the weight in pounds of a puppy after 17 months

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6 0
3 years ago
Question below. Please answer it, its math.
AleksAgata [21]

Answer:

- 0.8

Step-by-step explanation:

The first thing we want to do here is simplify the expression -

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= \frac{3}{5} * 2x + \frac{3}{5} * 5 - 2x, Focus on simplifying the expression " \frac{3}{5} * 2x + \frac{3}{5} * 5 "

= 2\cdot \frac{3}{5}x+5\cdot \frac{3}{5} - 2x

= \frac{6x}{5}+3 - 2x, Combine fractions

= -\frac{4x}{5} + 3

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- 4 / 5 = - 0.8,

Solution = - 0.8

4 0
3 years ago
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