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Oksana_A [137]
3 years ago
9

If a square has a side length of 11, what is the area

Mathematics
2 answers:
kicyunya [14]3 years ago
5 0
11*11=121
hope this helps and please give brainliest!
aliina [53]3 years ago
4 0
121 is the area of the square
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Pls give answer for 9c thanks
harina [27]

Answer:

probability for 3 on a dice (P3) in one dice =

\frac{1}{6}

probability for even no. of a dice (Pe) =

\frac{3}{6}  =  \frac{1}{2}

Therefore, the probability of finding 3 on one dice and even on another (P) = P3 + Pe

=  \frac{1}{6}  +  \frac{1}{2}  =  \frac{1 + 3}{6}  =  \frac{4}{6}  =  \frac{2}{3}

7 0
1 year ago
According to one cosmological theory, there were equal amounts of the two uranium isotopes 235U and 238U at the creation of the
FromTheMoon [43]

Answer:

6 billion years.

Step-by-step explanation:

According to the decay law, the amount of the radioactive substance that decays is proportional to each instant to the amount of substance present. Let P(t) be the amount of ^{235}U and Q(t) be the amount of ^{238}U after t years.

Then, we obtain two differential equations

                               \frac{dP}{dt} = -k_1P \quad \frac{dQ}{dt} = -k_2Q

where k_1 and k_2 are proportionality constants and the minus signs denotes decay.

Rearranging terms in the equations gives

                             \frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt

Now, the variables are separated, P and Q appear only on the left, and t appears only on the right, so that we can integrate both sides.

                         \int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt

which yields

                      \ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2,

where c_1 and c_2 are constants of integration.

By taking exponents, we obtain

                     e^{\ln |P|} = e^{-k_1t + c_1}  \quad e^{\ln |Q|} = e^{-k_12t + c_2}

Hence,

                            P  = C_1e^{-k_1t} \quad Q  = C_2e^{-k_2t},

where C_1 := \pm e^{c_1} and C_2 := \pm e^{c_2}.

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

                                 P(0) = Q(0) = C

Substituting 0 for P in the general solution gives

                         C = P(0) = C_1 e^0 \implies C= C_1

Similarly, we obtain C = C_2 and

                                P  = Ce^{-k_1t} \quad Q  = Ce^{-k_2t}

The relation between the decay constant k and the half-life is given by

                                            \tau = \frac{\ln 2}{k}

We can use this fact to determine the numeric values of the decay constants k_1 and k_2. Thus,

                     4.51 \times 10^9 = \frac{\ln 2}{k_1} \implies k_1 = \frac{\ln 2}{4.51 \times 10^9}

and

                     7.10 \times 10^8 = \frac{\ln 2}{k_2} \implies k_2 = \frac{\ln 2}{7.10 \times 10^8}

Therefore,

                              P  = Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} \quad Q  = Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}

We have that

                                          \frac{P(t)}{Q(t)} = 137.7

Hence,

                                   \frac{Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} }{Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}} = 137.7

Solving for t yields t \approx 6 \times 10^9, which means that the age of the  universe is about 6 billion years.

5 0
3 years ago
Find three consecutive odd integers such that six times the second decreased by twice the first is equal to twenty more than the
Kitty [74]
Let
x--------> the first <span>odd integer
x+2-----> </span>the second odd integer
x+4-----> the third odd integer

we know that
6(x+2)-2x=20+(x+2)+(x+4)
6x+12-2x=26+2x
4x-2x=26-12
2x=14
x=7

the answer is 
the numbers are
7, 9 and 11
6 0
3 years ago
Please help me I have been stuck for a while
tatyana61 [14]

Answer:

∛49.

Step-by-step explanation:

1/2 2 and √9 ( = 3) are rational.

∛49 = 3.65930571......

- the number goes on without bounds.

4 0
3 years ago
Which of the following best describes a bisector of an angle? A. The set of all points included between two sides of a given ang
Illusion [34]

That would be B.

The set of points are all on the line which is a bisector.

5 0
3 years ago
Read 2 more answers
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