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Sati [7]
3 years ago
9

2 1/3 divided by 3/4

Mathematics
2 answers:
TiliK225 [7]3 years ago
8 0

Answer:

3 1/9

Step-by-step explanation:

2 1/3 divided by 3/4

= 7/3 divided by 3/4

= 7/3 x 4/3

= 7 x 4 over 3 x 3

= 28 over 3 x 3

= 28/9

= 3 1/9

liubo4ka [24]3 years ago
8 0

Answer:

28/9

Step-by-step explanation:

  • <u>\frac{7}{3}  \div  \frac{3}{4}  \\  \\  \frac{7}{3}  \times  \frac{4}{3}  =  \frac{28}{9}</u>
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⇒ 8x -2x= -1+ 3
⇒ 6x = 2
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⇒ x= 1/3

The final answer is x= 1/3~
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Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
Complete the table below.<br> X Y=3x^2 Y=3x<br> 0 0 1<br> 1<br> 2
wlad13 [49]

Answer:

y= 3x^2 y= 3^x

1. 3. 3

2. 12. 9

Step-by-step explanation:

3(1)^1

3

3^1

3

3(2)^2

3(4)

12

3^2

9

5 0
2 years ago
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