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3 years ago

What is the answer to this expression 9-(3-6x)

Mathematics

2 answers:

Fudgin [204]3 years ago

6 0

Simplified would be 6+6x

katovenus [111]3 years ago

4 0

The answer simplified -6x I think

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Please, Help Quick! Thank you!!!

r-ruslan [8.4K]

You can say 99 children or 39 children and 44 adults

7 0

3 years ago

Read 2 more answers

Which of the following is the independent variable of G(F(y)) ?

alisha [4.7K]

Given:

The composition of functions is G(F(y)).

To find:

The independent variable of G(F(y)).

Solution:

Independent variable is the variable whose value independent from other variable. It means the value of independent variables is not depend on the other variable.

We know that G(F(y)) can be written as

$G(F(y))=(G\circ F)(y)$

Here, the value of function G depends on F(y) and the value of F(y) depend on variable y. But value of y does not depend on any variable. So, y is the independent variable of G(F(y)).

Therefore, the correct option is C.

5 0

3 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

4 years ago

If a die is rolled one time find these probabilities

olga_2 [115]

Of getting less than 7: 100%
of getting a number greater than or equal to 3: 4/6 or 67%

7 0

3 years ago

Do you have an equal chance of landing in either 1 or 4?

vitfil [10]

Answer:

Yes

Step-by-step explanation:

Since the circle is split into 6 pieces, we can split the probability of landing on each section into fractions

There is one piece with the number 1 on it, so there is a 1/6 chance of landing on that.

There are 3 pieces with the number 2 on it, so there is a 3/6 chance of landing on it, simplifies that would be 1/2

There is one piece with the number 3 on it, so there is a 1/6 chance of landing on that.

There is one piece with the number 4 on it, so there is a 1/6 chance of landing on that.

Since the pieces with a 1 and 4 on the both have a 1/6 probabilit of landing, there is an equal chance on landing on either tile.

4 0

3 years ago