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Degger [83]
3 years ago
15

The formula to determine energy is e=1/2mv^2. what is the formula solved for v?

Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0
Just rearrange for v here, 
e = 1/2 mv²
2e = mv²
v² = 2e / m
v = √(2e/m)

Hope this helps!
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This is a polygon and I need help finding the missing angle ?
allsm [11]
First, you need to know that the total (degrees) of the interior angles is 360 because this is a quadrilateral.

The unnumbered angle is 109 degrees. We know this because the angle labeled 71 degrees and the unnumbered angle are supplementary. So you subtract 180 from 71 to get 109. 
180-71=109

To solve for x, we need to realize the other numbers playing into the angles' values. To make solving this easier, I'm gonna assign letters to the angles. 

(10x+6) is angle A. 

(13x-2) is angle B. 

(8x-1) is angle C.

and 109 (the one we solved) is angle D. 

We know that the total of the interior angles is 360, so we can add the 2 from angle B and the 1 from angle C to 360. This is because these numbers are subtracted from the other values. 
360+2+1=363

Now, we have to subtract the 6 from angle A from 363, because the 6 is added to the other values. 
363-6=357

Now we have to subtract 109 from 357 because you want to get the x's by themselves. Since you're solving for x. 
357-109=248

That leaves you with 248. Now you add all the x's up to get the total number of x's. You have 10x from angle A, 13x from angle B, and 8x from angle C. 
10x+13x+8x=31x

You get 31x. To get what x is, you divide 248 by 31. 
\frac{248}{31} =8

That equals 8. So now that you know that x equals 8, if you need to find the values of the angles, you just plug in the numbers into the formulas. 

(10(8))+6= 86
(13(8))-2=102
(8(8))-1=63
109

Check your work by plugging your answers in and seeing if they add up to 360. 
86+102+63+109=360

Which they should:)

So...
angle A= 86
angle B=102
angle C=63
angle D=109

and x=8



Hope this helped!!!
4 0
3 years ago
Which of the following is and example of a random event? A. A mailman delivering the mail around 11 a.m. each day B. The day a n
Ronch [10]
Only C & D are examples of Random Event
8 0
3 years ago
based only on the inormation given in the diagram, which congruence theorems or postulates could be the given as reasons why abc
Fudgin [204]

Answer: 1. HA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

2. HL can be a reason to show given triangles are congruent as the triangles are right triangle with equal legs and hypotenuse.

3. SAS can be a reason to show given triangles are congruent as there are  two congruent sides in both triangles and included angles ∠A=∠D=90° [right angle].

4. LA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

5. AAS  cannot be a reason to show given triangles are congruent as it is not given that they have two angles common in both the triangles.

6.SSS can be a reason to show given triangles are congruent as it is shown that all the sides of one triangle is congruent to the other.

HOPE THIS HELPS

6 0
2 years ago
Which of the followings explains the difference between a regular subquery and a correlated subquery?
Fynjy0 [20]
Correlated means that they relate so probably this might help
5 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2500 megawatts ​(2.5 ​gigawatts) of power. Complete p
marishachu [46]

Answer:

<u>The correct answer is A. 7,665'000,000 kilowatt-hours per year and B. 766,500 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,500 Megawatts or 2.5 Gigawatts

2. Let's resolve the questions a and b:

Part A

Assuming wind farms typically generate 35​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,500 * 0.35 = 875 Megawatts

875 Megawatts = 875 * 1,000 Kilowatts = 875,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

875.000 Kw generated by the farms means that are capable of produce 875,000 kw per hour of energy

875,000 * 24 = 21'000,000 kilowatt-hours per day

<u>21'000,000 * 365 = 7,665'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (7,665'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  7,665'000,000/10,000 = 766,500</u>

4 0
2 years ago
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