Answer:
The plans will cost the same when the amount you have to pay for talking for "x" minutes on Plan A is the same has what you have to pay for talking for the same number of "x" minutes when using Plan B.
$$ Plan A = $$ Plan B
To find the charge on each plan we add the base rate to the per minute call rate for each.
Plan A = $27 + $0.11x
Plan B = $13 + $0.15x
Let's drop the $ sign for now and get rid of the decimal point by multiplying by 100.
2700 + 11x = 1300 + 15x
Subtracting 11x and 1300 from both sides:
4x = 1400
x = 350 min.
Using this result the plans both cost $65.50 for 350 min of talk time.
Step-by-step explanation:
boom :)
Use slander and search textbook up it will show up with answers
Answer:
The answer is 2427.5
Step-by-step explanation:
The fraction consists of two numbers and a fraction bar: 4,855/200
The number above the bar is called numerator: 4,855
The number below the bar is called denominator: 200
The fraction bar means that the two numbers are dividing themselves.
To get fraction's value divide the numerator by the denominator:
Value = 4,855 ÷ 200
To calculate the greatest common factor, GCF:
1. Build the prime factorizations of the numerator and denominator.
2. Multiply all the common prime factors, by the lowest exponents.
Factor both the numerator and denominator, break them down to prime factors:
Prime Factorization of a number: finding the prime numbers that multiply together to make that number.
4,855 = 5 × 971;
4,855 is a composite number;
In exponential notation:
200 = 2 × 2 × 2 × 5 × 5 = 23 × 52;
200 is a composite number;
Answer:
The equation of the line is y =
x + 2
Step-by-step explanation:
The form of the equation that passes through two points (x1, y1) and (x2, y2) is y = m x + b, where
- m is the slope of the line whose rule is
- b is the y-intercept, you can find it by substituting x, y in the equation by (x1, y1) OR (x2, y2)
Let us solve the question:
∵ The line passes through the points (-3, -2) and (3, 6)
∴ x1 = -3 and x2 = 3
∴ y1 = -2 and y2 = 6
→ Use the rule of m to find it
∵ ![m=\frac{6-(-2)}{3-(-3)}=\frac{6+2}{3+3}=\frac{8}{6}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B6-%28-2%29%7D%7B3-%28-3%29%7D%3D%5Cfrac%7B6%2B2%7D%7B3%2B3%7D%3D%5Cfrac%7B8%7D%7B6%7D)
→ Simplify it by dividing up and down by 2
∴ m = ![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
→ Substitute its value in the form of the equation above
∴ y =
x + b
→ To find b substitute x and y by x1 and y1
∴ -2 =
(-3) + b
∴ -2 = -4 + b
→ Add 4 to both sides
∴ -2 + 4 = -4 + 4 + b
∴ 2 = b
→ Substitute it in the form of the equation
∴ y =
x + 2
∴ The equation of the line is y =
x + 2
Answer:
For this case we want to check if the true mean for the depth of groves cut into aluminium by a machine is equal to 1.7 (null hypothesis) and the alternative hypothesis would be the complement different from 1.7. And the best system of hypothesis are:
Null hypothesis: ![\mu =1.7](https://tex.z-dn.net/?f=%5Cmu%20%3D1.7)
Alternative hypothesis ![\mu \neq 1.7[/tx]And the best system of hypothesis are:3. This two-sided test: H0: μ = 1.7 mm H1: μ ≠ 1.7 mmStep-by-step explanation:For this case we want to check if the true mean for the depth of groves cut into aluminium by a machine is equal to 1.7 (null hypothesis) and the alternative hypothesis would be the complement different from 1.7. And the best system of hypothesis are:Null hypothesis: [tex]\mu =1.7](https://tex.z-dn.net/?f=%5Cmu%20%5Cneq%201.7%5B%2Ftx%5D%3C%2Fp%3E%3Cp%3EAnd%20the%20best%20system%20of%20hypothesis%20are%3A%3C%2Fp%3E%3Cp%3E3.%20This%20two-sided%20test%3A%0A%3C%2Fp%3E%3Cp%3EH0%3A%20%CE%BC%20%3D%201.7%20mm%0A%3C%2Fp%3E%3Cp%3EH1%3A%20%CE%BC%20%E2%89%A0%201.7%20mm%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EFor%20this%20case%20we%20want%20to%20check%20if%20the%20true%20mean%20for%20the%20depth%20of%20groves%20cut%20into%20aluminium%20by%20a%20machine%20is%20equal%20to%201.7%20%28null%20hypothesis%29%20and%20the%20alternative%20hypothesis%20would%20be%20the%20complement%20different%20from%201.7.%20And%20the%20best%20system%20of%20hypothesis%20are%3A%3C%2Fp%3E%3Cp%3ENull%20hypothesis%3A%20%5Btex%5D%5Cmu%20%3D1.7)
Alternative hypothesis [tex]\mu \neq 1.7[/tx]
And the best system of hypothesis are:
3. This two-sided test:
H0: μ = 1.7 mm
H1: μ ≠ 1.7 mm