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beks73 [17]
4 years ago
8

Somebody please help me with this problem.

Mathematics
1 answer:
irga5000 [103]4 years ago
8 0

Answer:

                \bold{p=\dfrac{2SA-2B}l}

Step-by-step explanation:

\bold{SA=\frac12lp+B}\\-B\qquad-B\\\\\bold{SA-B=\frac12lp}\\{}\qquad^{\times2}\qquad^{\times2}\\\\\bold{2SA-2B=lp}\\{}\qquad\div l\qquad\div l\\\\\bold{\dfrac{2SA-2B}{l}=p}

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Given that 2sin^2 theta + sin theta -1 = 0, find the two values for sin theta.
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2sin^2 θ + sin θ - 1 = 0
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3 years ago
write an equation that is the slope-intercept form of the equation of the line that passes through (1,2) and is parallel to 4x-2
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