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beks73 [17]
3 years ago
8

Somebody please help me with this problem.

Mathematics
1 answer:
irga5000 [103]3 years ago
8 0

Answer:

                \bold{p=\dfrac{2SA-2B}l}

Step-by-step explanation:

\bold{SA=\frac12lp+B}\\-B\qquad-B\\\\\bold{SA-B=\frac12lp}\\{}\qquad^{\times2}\qquad^{\times2}\\\\\bold{2SA-2B=lp}\\{}\qquad\div l\qquad\div l\\\\\bold{\dfrac{2SA-2B}{l}=p}

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I NEED HELP WITH THIS QUESTION PLEASE!!
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Answer:

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Step-by-step explanation:

100x8= 800

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Hope This Helped!

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2 years ago
The graph below shows the length of Jutta's hair over a 6 month period. Each point represents a measurement at the beginning of
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What is the classification for this polynomial?6
Fantom [35]

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6 0
2 years ago
Please answer this question now
Rashid [163]

Answer:

54

Step-by-step explanation:

To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.

The perimeter of the given triangle = IK + KM + MI

IK = IJ + JK = 13

KM = KL + LM = ?

MI = MN + NI ?

Let's find the length of each tangents.

NI = IJ = 5 (tangents from external point I)

JK = IK - IJ = 13 - 5 = 8

JK = KL = 8 (Tangents from external point K)

LM = MN = 14 (Tangents from external point M)

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IK = IJ + JK = 5 + 8 = 13

KM = KL + LM = 8 + 14 = 22

MI = MN + NI = 14 + 5 = 19

Perimeter = IK + KM + MI = 13 + 22 + 19 = 54

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2 years ago
Your savings account pays 2.5% interest per year. How much interest does the account pay per month.
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Answer:

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2 years ago
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