3 years ago

Given that 2sin^2 theta + sin theta -1 = 0, find the two values for sin theta.

1 answer:

8 0

2sin^2 θ + sin θ - 1 = 0
2sin^2 θ + 2sin θ - sin θ - 1 = 0
2sin θ(sin θ + 1) - 1(sin θ + 1) = 0
(2sin θ - 1)(sin θ + 1) = 0
2sin θ - 1 = 0 or sin θ + 1 = 0
sin θ = 1/2 or sin θ = -1

The two values of sin θ are 1/2 and -1

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If 3 p +3 4 =90

klemol [59]

3p + 34 = 90
3p = 90 - 34
3p = 56
p = 56/3
p = 18.67 (thats rounded)

2r + 44 = 76
2r = 76 - 44
2r = 32
r = 32/2
r = 16

53 + 6s = 1421
6s = 1421 - 53
6s = 1368
s = 1368/6
s = 228

" the product " means multiply
p x r x s = 18.67 x 16 x 228 = 68,108.16

8 0

4 years ago

Solve the inequality -2x < 5, illustrating your solution on a number line.

Over [174]

Answer:

No.

Step-by-step explanation:

Let's first and try to isolate x.

-2x < 5

(Divide by -2)

x > -5/2 ( < changes to > b/c it was divided by a negative)

x > -2.5