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3 years ago

1. Solve: n^4 - 12n^2 = -32

Mathematics

2 answers:

fgiga [73]3 years ago

5 0

Answer:

n=2sr2,-2sr2,-2,2

Step-by-step explanation:

sr stands for quare root

mojhsa [17]3 years ago

4 0

Answer:

n = ± 2√2, ± 2

Step-by-step explanation:

1. Move all terms to one side

n^4 - 12n^2 + 32 = 0

2. Factor n^4 - 12n^2 +32

(n^2 - 8)(n^2 - 4) = 0

3. Solve for n

n = ± 2√2, ± 2

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Write each sequence as a function.

Fiesta28 [93]

Answer: $f(n)=3^{n-1}$

Step-by-step explanation:

Given Recursive formula : $a_{n+1} = 3a_n,$ , $a_1=1$

Then, $a_2=a_{1+1} = 3a_1=3(1)=3$

$a_3=a_{2+1} = 3a_2=3(3)=9$

$a_4=a_{3+1} = 3a_3=3(9)=27$

We can write it as : $f(n)=3^{n-1}$

such that

n $f(n)=3^{n-1}$

1 $f(1)=3^{1-1}=1$

2 $f(2)=3^{2-1}=3^1=3$

3 $f(3)=3^{3-1}=3^2=9$

Hence, the required function: $f(n)=3^{n-1}$

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3 years ago

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The length of a rectangle is 2 cm longer than its width if the perimetier of the rectangle is 44cm, find its area

Natasha2012 [34]

L=w+2 and 2w+2l=44

substitute equation for length in perimeter equation

2w+2(w+2)=44
2w+2w+4=44
4w+4=44
4w=40
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substitute width into length equation to get length

l=10+2
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a=lw
a=12*10
a=120 cm^2

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Nat2105 [25]

Answer:

Step-by-step explanation:

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pickupchik [31]

Answer:

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Step-by-step explanation:

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3 years ago

The radius of one circle is three the time radius of another circle. The sum of their areas is 12pi. Find the radius of each cir

zlopas [31]

$\displaystyle\\
\begin{cases}
R_1 = 3R_2\\
\pi R_1^2 +\pi R_2^2=12\pi ~~~\Big|~~:\pi 
\end{cases} \\ \\ 
\begin{cases} 
R_1 = 3R_2\\
R_1^2 + R_2^2=12 
\end{cases} \\ \\ 
(3R_2)^2+ R_2^2=12 \\ \\ 
9R_2^2 + R_2^2=12 \\ \\ 
10R_2^2=12\\\\
R_2^2 = \frac{12}{10} = \frac{6}{5} \\ \\ 
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