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MAXImum [283]
3 years ago
15

Find the mean, median, and inter

Mathematics
2 answers:
Eva8 [605]3 years ago
7 0

Answer:

Step-by-step explanation:

The mean is 15.9

The median is 16

The interquartile range is 14.5

bagirrra123 [75]3 years ago
3 0

Answer:

Mean=15.9

Median=16

Interquartile=14.5

Step-by-step explanation:

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Jim bought the game system on sale for $195. Kaylen bought the same system at full price for $250. How much was the sale for whe
castortr0y [4]

Answer:

The game system that Jim bought had the sale of $55 off.

Step-by-step explanation:

Jim sale price = $195

Kaylen price = $250

250 -195 = 55

7 0
3 years ago
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I need help on 11, 12 and 13 please ... :(
Lynna [10]
Question 11= B
Question 13= C
I don't know how to do question 12
6 0
3 years ago
At a sale, dresses were sold for $90 each. This price was 75% of a
gulaghasi [49]

Answer:

A dress originally costs $120

Step-by-step explanation:

To find the original cost of the dress, we will follow the steps below;

let x represent the original cost of the dress

75% of x  = $90

\frac{75}{100}  ×    x   = $90

\frac{75X}{100}  =   $90

MULTIPLY both-side of the equation by 100

\frac{75X}{100} × 100 =   $90×100

At the right-hand side of the equation, 100 will cancel out 100, leaving us with just 75x

75x = $9000

DIVIDE both-side of the equation by 75

75x/75 = $9000/75

At the left-hand side of the equation 75 will cancel-out 75 leaving us with just x

x=  $9000/75

x = $120

A dress originally costs $120

3 0
3 years ago
Si un cono lo obtienes haciendo girar un triángulo rectángulo cuya base es de 10cm y su altura es de 16cm ¿cuánto mide el radio
rodikova [14]

Answer:

10 cm.

Step-by-step explanation:

In order to better understand this question, I will attach an allusive image to the question.

Keep in mind that in this case the base of the triangle is equal to the radius of the base of the cone since the triangle rotates on its own axis, therefore the measurement of the base corresponds to 10 cm, therefore the radius measures 10 cm.

5 0
3 years ago
If f(x) = integral of 1/ (sqrt of t^3 +2)dt, then f'1 = ?
mihalych1998 [28]
Differentiating an integral removes the integral.

f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
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