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vichka [17]
3 years ago
6

Auto accidents by teens

Mathematics
1 answer:
alexgriva [62]3 years ago
8 0
There are many, due to texting, food, and music
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Find the value of X(2x + 4) (2x-9)
kotykmax [81]

2x +4)° 2x-9)°= 4x  2 +8x−9=3

 Pull out like factors :

  2x + 4  =   2 • (x + 2) (4 • (x + 2) • x) -  9

4x • (x + 2) -  9

Factoring  4x2+8x-9  

The first term is,  4x2  its coefficient is  4 .

The middle term is,  +8x  its coefficient is  8 .

The last term, "the constant", is  -9  

Step-1 : Multiply the coefficient of the first term by the constant   4 • -9 = -36  

Step-2 : Find two factors of  -36  whose sum equals the coefficient of the middle term, which is   8 .

     -36    +    1    =    -35  

     -18    +    2    =    -16  

     -12    +    3    =    -9  

     -9    +    4    =    -5  

     -6    +    6    =    0  

     -4    +    9    =    5  

     -3    +    12    =    9  

     -2    +    18    =    16  

     -1    +    36    =    35

x=3

6 0
3 years ago
Read 2 more answers
Wright an Expression to represent: three minus the product of two and a number z
Nookie1986 [14]

Answer:

2z-3

Step-by-step explanation:

7 0
3 years ago
What is the slope of a line passing through (3, 4) and (5,8)?
Licemer1 [7]

Answer:

2

Step-by-step explanation:

slope=\frac{y_2-y_1}{x_2-x_1} \\\frac{8-4}{5-3} =\frac{4}{2} =2\\slope=2

8 0
2 years ago
6.7 divided by 643.2 find the quotient
katrin2010 [14]

Answer:

1/96 or 0.01041666667

Step-by-step explanation:

5 0
3 years ago
Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres​
mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

W = 15

Solving for L:

L = 30 − W

L = 15

So the maximum area is:

A = WL

A = (15)(15)

A = 225

3 0
3 years ago
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