Pythagorean thoerem
we imagine the wall as a leg of a right triangle, the ladder is the hypotonuse and the distance from the bottom of the ladder to the wall is the other leg
so if we have a right triangle with leg length a and b and hypotnuse length c then
a²+b²=c²
so
given that one of the legs is 9ft (9 ft is the height of the triangle)
and the hypotnuse is 12 ft (length of ladder)
then say the last leg is x
so
x²+9²=12²
x²+81=144
mius 81 both sides
x²=63
sqrt both sides
x=√63
x=3√7
you should place it 3√7ft or about 7.9 or 8ft away
The answer is 197.
1 and 2 = 3
3+2=5
3+3=6
6x0=0
24x8=192
5+0=5
192+5=197
4x+30=90
4x = 60
x = 15
answer is B. 15
Answer:
see explanation
Step-by-step explanation:
(1)
CD = CE - DE = 8 - 2 = 6
CB = CD = 6 ( given as congruent ) , thus
AC = AB + CB = 4 + 6 = 10
(2)
∠ 2 + ∠ BCD + ∠ DCF = 180° ( sum of angles on a straight line )
∠ 2 + 60° + 70° = 180°
∠ 2 + 130° = 180° ( subtract 130° from both sides )
∠ 2 = 50°
