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aivan3 [116]
2 years ago
11

HELP NEEDED!!! WILL MARK BRAINLIEST!!!

Mathematics
1 answer:
finlep [7]2 years ago
7 0

Answer:

  x = ±√ 1.667 = ± 1.29099

Step-by-step explanation:

List factors of p: 3,8

List factors of q: 4,5

List possible zeros: +/- p/q (0 -8 1.667

(looked it up )

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Find the area of the shaded portion in the square. Show all work for full credit.
kumpel [21]
Well, what I would do [not sure if it's the correct way], is use the white area as a sector of a circle. The top right of the box is the center of the circle, so the radius is 6.
Then, by the white portion being one quarter of the circle (90° out of 360°), I could calculate the that pink shaded region = the total square (6×6) minus the white sector.
So area (A) of white sector (s): A(s) = 1/4×pi×r^2
A(s) =  \frac{\pi {r}^{2} }{4}  =  \frac{\pi  \times {6}^{2} }{4}  \\ A(s) =  \frac{36\pi}{4}  = \frac{9\pi}{1}  = 9x3.142 \\ A(s) = 28.27
36 - 28.27 = 7.73
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3 years ago
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DaniilM [7]
Obtuse angle that’s the answer
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3 years ago
Two Step Equations<br><br> 9=5- 9/3
Alex787 [66]
9=5 -y/3
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6 0
2 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
2 years ago
Find the product -1.2(0.04)
patriot [66]

Answer:

-0.048

Step-by-step explanation:

-1.2 * 0.04 = -1.2 * 4 / 100 = -4.8 / 100 = -).048

4 0
2 years ago
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