Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).
<h3>What are the mean and the standard error for each sample?</h3>
Considering the data given:
<h3>What is the mean and the standard error for the distribution of differences?</h3>
The mean is the subtraction of the means, hence:
The standard error is the square root of the sum of the variances of each sample, hence:
<h3>What is the confidence interval?</h3>
It is given by:
We have a 95% confidence interval, hence the critical value is of z = 1.96.
Then, the bounds of the interval are given as follows:
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
0.66
Step-by-step explanation:
As division is always done before addition you would divide the 6 by 10 and then divide the 6 by 100. 6 divided by 10 is equal to 0.6 as you move the decimal point to the left once. 6 divided by 100 is equal to 0.06 as you move the decimal point to the left twice. Addition is always done after division so you would add 0.6 and 0.06 together. This will give you 0.66 as your answer.
You would do 5 times 4 which is 20. then count how many zero's there are and put them after the 20.
Checking if the sequence is an arithmetic sequence
7 - 1 = 6
13 – 7 = 6
Therefore the sequence is arithmetic, with a_0 = 1 and d = 6
a_n = a_0 + (n-1)d
a_30 = 1 + (29)(6)
= 175
Therefore the 30th term is 175.
