Lf f(x) = 5x, what is f^-1(x)?

Mathematics

1 answer:

Nonamiya [84]3 years ago

7 0

Answer: $f^{-1}(x)=\frac{x}{5}$

Step-by-step explanation:

By definition the domain of an inverse function $f^-1(x)$ is the range of f(x) and the range of the inverse function is equal to the domain of the principal function f(x).

If you have a function $f(x)=5x$ , then to find the inverse function, follow these steps:

1. Make $y=f(x)$

$f(x)=y=5x$

$y=5x$

2. Solve for the variable "x":

$x=\frac{y}{5}$

3. Exchange the variable "x" with the variable "y":

$y=\frac{x}{5}$

4. Exchange "y" with $f^{-1}(x)$ . Then the inverse function is:

$f^{-1}(x)=\frac{x}{5}$

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